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Suppose we have an integer array A. We have to find the contiguous subarrays which length will be at least one, and that has the largest sum, and also return its sum. So if the array A is like A = [-2, 1, -3, 4, -1, 2, 1, -5, 4], then the sum will be 6. And the subarray will be [4, -1, 2, 1]To solve this we will try to use the Dynamic programming approach.define an array dp same as the size of A, and fill it with 0dp[0] := A[0]for i = 1 to the size of A ... Read More
Here we will see the Count and Say sequence. This is a sequence whose few terms are like below −111211211111221The string will be read like1 (One)11 (One 1) So read the previous 1, and say “One 1”21 (Two 1) So read the previous 11, and say “Two 1”1211 (One 2 one 1) So read the previous 21, and say “One 2 one 1”111221 (One 1 one 2 two 1) So read the previous 1211, and say “One 1 one 2 two 1”Suppose we have a number n, 1
Suppose we have two strings str and sub_str. We have to find the first occurrence of sub_str in the str. So if the string str is “helloworld”, and substring is “lo”, then the result will be 3.This can be done using the strstr() function in C. We have to design another function that is similar to the strstr() in C.To solve this, follow these steps −i := 0, j := 0, m := length of sub_str and n := length of strif m = 0, then return 0while i < n and n – i + 1 = m, doif ... Read More
Suppose we have a sorted list A. We have to return the length of the array after removing all duplicate entries. We have to perform this in O(1) extra space. So we have to do the operation in-place.For an example, suppose A = [1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6] Then the output will be 6, as there are six distinct elements.To solve this, follow these steps −If the list is empty, return 0otherwise, initially take prev = first element of A. And define length = 0for i := 1 to n-1, doif ... Read More
Suppose we have two sorted lists A and B. We have to merge them and form only one sorted list C. The size of lists may different.For an example, suppose A = [1,2,4,7] and B = [1,3,4,5,6,8], then merged list C will be [1,1,2,3,4,4,5,6,7,8]We will solve this using recursion. So the function will work like below −Suppose the lists A and B of function merge()if A is empty, then return B, if B is empty, then return Aif value in A
Suppose we have a set of strings in an array. We have to find the Longest Common Prefix amongst the string in the array. Here we will assume that all strings are lower case strings. And if there is no common prefix, then return “”.So if the array of a string is like ["school", "schedule", "Scotland"], then the Longest Common Prefix is “sc” as this is present in all of these string.To solve this, we will take the first string as curr, now take each string from the array and read them character by character, and check the characters between ... Read More
A Module is a combination of both code and data that has a name, declares dependencies on other modules, exports packages that contain the public types that can be accessible outside this module and specifies the services it uses or the service implementations it provides. All of these have specified in a module-info.java file, which is included in the root directory of a module.There are two types of "export" clause can be used in "module-info.java" file.1) export : By default, the type public of a module is no longer visible outside the module. To make the public types of a given package visible from ... Read More
Suppose we have a non-empty integer array, we have to find the minimum number of moves that are required to make all array elements equal, where a move is incrementing or decrementing a selected element by 1. So when the array is like [1, 2, 3], then the output will be 2, as 1 will be incremented to 2, and 3 will be decremented to 2.To solve this, we will follow these steps −sort the array numsset counter as 0for i in nums, docounter := counter + absolute of (i – nums[length of nums / 2])return counterExample(Python)Let us see the ... Read More
Here we will see how to make a stack, that can perform push, pop, top, and retrieve the min element in constant time. So the functions will be push(x), pop(), top() and getMin()To solve this, we will follow these steps −Initialize the stack by min element as infinityFor push operation push(x)if x < min, then update min := x, push x into stackFor pop operation pop()t := top elementdelete t from stackif t is min, then min := top element of the stackFor top operation top()simply return the top elementfor getMin operation getMin()return the min elementExampleLet us see the following ... Read More
Consider we have a linked list, and we have to check whether there is any cycle or not. To represent the cycle in the given linked list, we will use one integer pointer called pos. This pos represents a position in the linked list where tail is connected. So if pos is -1, then there is no cycle present in the linked list. For example, the linked list is like [5, 3, 2, 0, -4, 7], and pos = 1. So there is a cycle, and tail is connected to the second node.To solve this, we will follow these steps ... Read More