Suppose we have a string S of lowercase letters; a duplicate removal operation will be performed. This will be done by choosing two adjacent and equal letters, and removing them.
We will repeatedly remove duplicates from S until no duplicates are remaining.
Return the string after all such duplicate removals have been completed. It is guaranteed that the answer is unique.
Suppose the string is “abbacaca”, then answer will be “caca”. At first delete duplicates bb, then string is “aacaca”, then remove aa, then string is “caca”, then no such duplicates are there.
To solve this, we will follow these steps −
Let us see the following implementation to get better understanding −
class Solution(object): def removeDuplicates(self, S): st =  i = 0 while i < len(S): if len(st)!=0 and st[-1]==S[i]: i+=1 st.pop(-1) else: st.append(S[i]) i+=1 return "".join(i for i in st) ob1 = Solution() print(ob1.removeDuplicates("abbacaca"))