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Suppose we have an array of n elements, and a positive integer s. We have to find the minimal length of a contiguous subarray, of which the sum is greater or equal to s. If there isn’t one, then return 0 instead. So if the array is like [2, 3, 1, 2, 3, 4] and sum is 7, then the output will be 2. This is the subarray [4, 3] has the minimum length for this case.To solve this, we will follow these steps −ans := 0, n := size of array A, j := 0 and sum := 0for ... Read More
Suppose we have an undirected tree; we have to find its diameter − the number of edges in the longest path in that tree is the diameter of that tree. Here tree is given as an edge list where edges[i] = [u, v] is a bidirectional edge between nodes u and v. Each node has labels in the set {0, 1, ..., edges.length}. So if the graph is like −The output will be 4.To solve this, we will follow these steps −Define a map ldefine a method called dfs(). this will take v, an array called visited, the graph and ... Read More
Suppose we have two integers representing the numerator and denominator of a fraction, we have to find fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. So if the numerator is 2 and denominator is 3, then the output will be “0.(6)”To solve this, we will follow these steps −if numerator is 0, then return 0define one array ansif the numerator < 0 and denominator > 0 or numerator 0 and denominator < 0, then insert negative symbol ‘-’ into the ans arraydivisor := |numerator| and dividend := |denominator|, remainder := divisor mod ... Read More
Suppose we have a linked list like l1 -> l2 -> l3 -> l4 -> … -> l(n-1) -> ln. We have to rearrange this list into the form l1 -> ln -> l2 -> l(n - 1) -> … and so on. Here the constraint is that, we cannot modify the values in the list nodes, only the node itself may be changed. So for example, if the list is like [1, 2, 3, 4, 5], then the output will be [1, 5, 2, 4, 3]To solve this, we will follow these steps −Define a method called reverse to ... Read More
Suppose we have a list, we have to sort this in O(n logn) time using constant space complexity, so if the list is like [4, 2, 1, 3], then it will be [1, 2, 3, 4]To solve this, we will follow these steps −Define a method for merging two lists in sorted, order, that method is merge(), this takes two lists l1 and l2.The sort list method will work like below −if head is null, or next of head is null, then return headslow := head, fast := head, and prev = nullwhile fast is not null and next of ... Read More
Suppose we have a binary tree; we have to flatten it into linked list in place. So if the tree is like −The output tree will be −To solve this, we will follow these steps −ser prev := nullDefine a recursive function solve(), that will take root as input.if root is null, then returnsolve(right of root)solve(left of root)right of root := prev, left of root := nullprev := rootLet us see the following implementation to get better understanding −Example Live Demo#include using namespace std; class TreeNode{ public: int val; TreeNode *left, *right; TreeNode(int data){ ... Read More
Suppose we have a binary tree; we have to find the Zigzag level order traversal. So for the first row, scan from left to right, then right to left from the second row, then again left to right and so on. So if the tree is like −The traversal sequence will be [[3], [20, 9], [15, 7]]To solve this, we will follow these steps −if the tree is empty, return empty listqueue := make a queue and insert root into the queue, create two empty lists res and res2, and set flag as Truewhile queue is not emptymake a list ... Read More
Suppose we have a char array representing tasks CPU need to do. This contains uppercase letters A to Z where different letters represent different tasks. The tasks could be done without original order. Each task could be done in one interval. For each interval, CPU could finish one job or just be idle. However, there is a non-negative cooling interval called n that means between two same tasks, there must be at least n intervals that CPU are doing different tasks or just be idle. We have to find the least number of intervals the CPU will take to finish ... Read More
Jdeps tool can be used to analyze the dependencies of our classes. The running of the "jdeps -jdkinternals jararchive.jar" command prints a list of all classes that use Java internal API. Jdeps tool returns a detailed description of the dependencies while Jdeprscan is another useful tool particularly used in combination with the "-for-removal" flag. This tool shows us all uses of deprecated API by a given jar archive, and only deprecated uses of jdk methods can be shown and can't use this tool to check for deprecation in third party jar.Jdeps tool:"jdeps" is a class dependency analyzer tool can be used for package level ... Read More
Suppose we have a sequence of number is called arithmetic if it consists of at least three elements and if the difference between any two consecutive elements is the same. So for example, these are arithmetic sequence: [1, 3, 5, 7, 9], [7, 7, 7, 7], [3, -1, -5, -9], But the following sequence is not arithmetic. [1, 1, 2, 5, 7]Now a zero-indexed array A consisting of N numbers is given. A slice of that given array is any pair of integers (P, Q) such that 0