Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
We have an example of PowerShell advanced function below and we will try to understand how mandatory parameter works.function math_Operation{ [cmdletbinding()] param([int]$val1, [int]$val2) Write-Host "Multiply : $($val1*$val2)" Write-Host "Addition : $($val1+$val2)" Write-Host "Subtraction : $($val1-$val2)" Write-Host "Divide : $($val1+$val2)" }When you execute the above example and don’t supply values then the script won’t ask you for the values, by default it will take the values and execute the program. See the execution below.PS C:\WINDOWS\system32> math_Operation Multiply : 0 Addition : 0 Subtraction : 0 Divide : 0Even if you have mentioned two variables ($val1, ... Read More
Before starting the Advance PowerShell function, assuming we know about the PowerShell function. You can check the explanation on the PowerShell function below.https://www.tutorialspoint.com/explain-the-powershell-functionHere, we will take the math function example that calculates the different types of operations. We already have a code with the simple function as shown below.function math_Operation{ param([int]$val1, [int]$val2) Write-Host "Multiply : $($val1*$val2)" Write-Host "Addition : $($val1+$val2)" Write-Host "Subtraction : $($val1-$val2)" Write-Host "Divide : $($val1+$val2)" }The above example is of the simple function. When you run the above code and run the function from the terminal and you can notice you will ... Read More
Suppose we have a linked list, we have to perform the insertion sort on this list. So if the list is like [9, 45, 23, 71, 80, 55], sorted list is [9, 23, 45, 55, 71, 80].To solve this, we will follow these steps −dummy := new Node with some random valuenode := given listwhile node is not null, newNode = next of node, dummyHead := next of dummy, prevDummyHead := dummywhile true −if dummyHead is not present, value of dummyHead > value of nodenext of node := dummyHeadnext of prevDummyHead := nodebreak the loopprevDummyHead := dymmyHead, and dummyHead = ... Read More
Suppose we have a binary tree. We have to return the preorder traversal of that tree. So if the tree is like −Then the preorder traversal will be: [3, 9, 20, 15, 7]To solve this, we will follow these steps −make empty lists called res and st.node := rootwhile node or st is not emptywhile node is not null, theninsert val of node into res, insert node into st and set node := left of nodetemp := last element of st, and delete last element of stif right of temp is available, thennode := right of tempreturn resLet us see ... Read More
Consider we have a linked list, and we have to check whether there is any cycle or not. To represent the cycle in the given linked list, we will use one integer pointer called pos. This pos represents a position in the linked list where tail is connected. So if pos is -1, then there is no cycle present in the linked list. For example, the linked list is like [5, 3, 2, 0, -4, 7], and pos = 1. So there is a cycle, and tail is connected to the second node. The constraint is that we cannot modify ... Read More
Suppose we have a 2D board containing X and O. Capture all regions surrounded by X. A region is captured by changing all Os into Xs in that surrounded region.XXXXXOOXXXOXXOXXAfter running the output will beXXXXXXXXXXXXXOXXTo solve this, we will follow these steps −If board is not present, then return blank boardfor i in range 0 to number of rows – 1 −if board[i, 0] = ‘O’, then make_one(board, i, 0)if board[i, length of row - 1] = ‘O’, then make_one(board, i, length of row – 1)for i in range 0 to number of cols – 1 −if board[0, i] = ... Read More
Suppose we have given a binary tree in which each node holds an integer key. We have to find the paths that sum to a given value. The path should start from root to leaf. We have to find the path where the sum is same.If the tree is like [5, 4, 8, 11, null, 13, 4, 7, 2, null, null, 5, 1], and sum is 22, then it will be −The paths are [[5, 4, 11, 2], [5, 8, 4, 5]].To solve this, we will follow these steps −Use the dfs function to solve this problem, the dfs is ... Read More
Suppose we have the inorder and postorder traversal sequence of a binary tree. We have to generate the tree from these sequences. So if the postorder and inorder sequences are [9, 15, 7, 20, 3] and [9, 3, 15, 20, 7], then the tree will be −Let us see the steps -Suppose the method is called buildTree with preorder and inorder listsroot := last node from the postorder, and delete first node from postorderroot_index := index of root.val from the inorder listleft or root := buildTree(subset of inorder from root_index + 1 to end, postorder)right or root := buildTree(subset of ... Read More
Suppose we have the inorder and preorder traversal sequence of a binary tree. We have to generate the tree from these sequences. So if the preorder and inorder sequences are [3, 9, 20, 15, 7] and [9, 3, 15, 20, 7], then the tree will be −Let us see the steps −Suppose the method is called buildTree with preorder and inorder listsroot := first node from the preorder, and delete first node from preorderroot_index := index of root.val from the inorder listleft or root := buildTree(preorder, subset of inorder from 0 to root_index)right or root := buildTree(preorder, subset of inorder ... Read More
Suppose we have a linked list. We have to reverse the nodes from position m to n. We have to do it in one pass. So if the list is [1, 2, 3, 4, 5] and m = 2 and n = 4, then the result will be [1, 4, , 3, 2, 5]Let us see the steps −There will be two methods, the reverseN() and reverseBetween(). The reverseBetween() will work as main method.define one link node pointer called successor as nullThe reverseN will work as follows −if n = 1, then successor := next of head, and return headlast ... Read More