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Complex Number Multiplication in C++
Suppose we have two strings that are representing complex numbers, we have to parse them and perform complex number multiplication, then return result as a string.
So if the input is like “1+-1i” and “1+-1i”, then the result will be “0+-2i”.
To solve this, we will follow these steps −
- aa := a pair of real and imaginary of first complex number
- bb := a pair of real and imaginary of second complex number
- x := aa.real * bb.real – aa.img*bb.img
- y := aa.real * bb.img + aa.img*bb.real
- return the string as “x+yi”
Let us see the following implementation to get better understanding −
Example
#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
string complexNumberMultiply(string a, string b) {
pair <int, int> aa = parse(a);
pair <int, int> bb = parse(b);
int x = aa.first * bb.first - aa.second * bb.second;
int y = aa.first * bb.second + aa.second * bb.first;
return to_string(x) + "+" + to_string(y) + "i";
}
pair <int, int> parse(string s){
pair <int, int> ret;
int plus = find(s.begin(), s.end(), '+') - s.begin();
int i = find(s.begin(), s.end(), 'i') - s.begin();
ret.first = stoi(s.substr(0, plus));
ret.second = stoi(s.substr(plus + 1, i - plus));
return ret;
}
};
main(){
Solution ob;
cout << (ob.complexNumberMultiply("1+-1i", "1+-1i"));
}Input
"1+-1i" "1+-1i"
Output
0+-2i
Updated on: 04-May-2020
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