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Articles on Trending Technologies
Technical articles with clear explanations and examples
How do you write a method in Java that can print object in array?
Exampleclass Shape{ private String shapeName; private int numSides; Shape(String shapeName, int numSides){ this.shapeName = shapeName; this.numSides = numSides; } public String toString(){ return shapeName + " has " + numSides + " sides."; } } class ObjectList{ private Object[] list = new Object[10]; private int numElement = 0; public void add(Object next){ list[numElement] = next; numElement++; } @Override public String toString(){ String str=""; int i=0; while(list[i] != null){ str += list[i]+""; i++; } return str; } } public class Driver{ public static void main(String[] args){ ObjectList list = new ObjectList(); Shape square = new Shape("square", 4); Shape hex = new Shape("hexagon", 6); list.add(hex); list.add(square); System.out.println(list); } }
Read MoreHow to add/subtract large numbers using Python?
You can add/subtract large numbers in python directly without worrying about speed. Python supports a "bignum" integer type which can work with arbitrarily large numbers. In Python 2.5+, this type is called long and is separate from the int type, but the interpreter will automatically use whichever is more appropriate.As long as you have version 2.5 or better, just perform standard math operations and any number which exceeds the boundaries of 32-bit math will be automatically (and transparently) converted to a bignum.examplea = 182841384165841685416854134135 b = 135481653441354138548413384135 print(a - b)OutputThis will give the output −47359730724487546868440750000
Read MoreHow to find Kaprekar numbers within a given range using Python?
A modified Kaprekar number is a positive whole number n with d digits, such that when we split its square into two pieces - a right hand piece r with d digits and a left hand piece l that contains the remaining d or d−1 digits, the sum of the pieces is equal to the original number (i.e. l + r = n).You can find Kaprekar numbers within a given range by testing each number for the given condition in the given range. exampledef print_Kaprekar_nums(start, end): for i in range(start, end + 1): ...
Read MoreHow to generate pyramid of numbers using Python?
There are multiple variations of generating pyramids using numbers in Python. Let's look at the 2 simplest formsExamplefor i in range(5): for j in range(i + 1): print(j + 1, end="") print("")OutputThis will give the output1 12 123 1234 12345ExampleYou can also print numbers continuously usingstart = 1 for i in range(5): for j in range(i + 1): print(start, end=" ") start += 1 print("")OutputThis will give the output1 2 3 4 5 6 7 8 9 10 11 12 13 14 15ExampleYou can also print these numbers in reverse usingstart = 15 for i in range(5): for j in range(i + 1): print(start, end=" ") start -= 1 print("")OutputThis will give the output15 14 13 12 11 10 9 8 7 6 5 4 3 2 1
Read MoreHow to Humanize numbers with Python?
If you want something that converts integers to words like 99 to ninety-nine, you have to use an external package or build one yourself. The pynum2word module is pretty good at this task. You can install it using −$ pip install pynum2wordThen use it in the following way −>>> import num2word >>> num2word.to_card(16) 'sixteen' >>> num2word.to_card(23) 'twenty-three' >>> num2word.to_card(1223)'one thousand, two hundred and twenty-three'If you want to get results like 1.23 million for 1, 230, 000, you can use the humanize library to do so. You can install it using −$ pip install humanizeThen use it in the following way ...
Read MoreImportance of Collectors.flatMapping() method in Java 9?
In Java 9, a new method added to the Collectors class: flatMapping(). It is similar to the Collectors.mapping() method in which the flatMapping() method allows us to handle nested collections. The Collectors.flatMapping() method takes a function to be applied to input elements and a collector to accumulate the elements passed through the function. Unlike the Collectors.mapping() method, the Collectors.flatMapping() method deals with a stream of elements that allows us to get rid of unnecessary intermediary collections.Syntaxpublic static Collector flatMapping(Function
Read MoreHow to identify and print all the perfect numbers in some closed interval [ 2, n ] using Python?
A perfect number is a positive integer that is equal to the sum of its proper divisors. The smallest perfect number is 6, which is the sum of 1, 2, and 3.You can find perfect numbers within a given range by testing each number for the given condition in the given range. exampledef print_perfect_nums(start, end): for i in range(start, end + 1): sum1 = 0 for x in range(1, i): # Check if a divisor, if it is, add to sum if(i % x == 0): sum1 = sum1 + x if (sum1 == i): print(i) print_perfect_nums(1, 300)OutputThis will give the output6 28
Read MoreHow to Display the multiplication Table using Python?
You can create the multiplication table for any number using a simple loop. exampledef print_mul_table(num): for i in range(1, 11): print("{:d} X {:d} = {:d}".format(num, i, num * i)) print_mul_table(5)OutputThis will give the output5 X 1 = 5 5 X 2 = 10 5 X 3 = 15 5 X 4 = 20 5 X 5 = 25 5 X 6 = 30 5 X 7 = 35 5 X 8 = 40 5 X 9 = 45 5 X 10 = 50
Read MoreHow to Find the Largest Among Three Numbers using Python?
You can create a list of the three numbers and call the max method to find the largest among them. examplemy_list = [10, 12, 3] print(max(my_list))OutputThis will give the output −12ExampleIf you want to calculate it yourself, you can create a simple function likedef max_of_three(a, b, c): if a > b and a > c: return a elif b > c: return b else: return c print(max_of_three(10, 12, 3))OutputThis will give the output −12
Read MoreHow to Solve Quadratic Equation using Python?
You can use the cmath module in order to solve Quadratic Equation using Python. This is because roots of quadratic equations might be complex in nature. If you have a quadratic equation of the form ax^2 + bx + c = 0, then,Exampleimport cmatha = 12 b = 8 c = 1 # Discriminent d = (b**2) - (4*a*c) root1 = (-b - cmath.sqrt(d)) / (2 * a) root2 = (-b + cmath.sqrt(d)) / (2 * a) print(root1) print(root2)OutputThis will give the output(-0.5+0j) (-0.16666666666666666+0j)
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