Bitwise Recursive Addition of Two Integers in C

sudhir sharma
Updated on 05-Aug-2020 08:00:49

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In this problem, we are given two numbers. Our task is to create a C program for the Bitwise recursive addition of two integers.The logic to find the sum using the Bitwise operations is similar to what we used to do when we were in preschool. For finding the sum, we used to add each digit of the number and if a carry is there, we add it to the next digit.We will do a similar thing, find the sum using the XOR operator and check for the carry using the AND operation. If there is a carry we will ... Read More

Bitwise OR of N Binary Strings in C++

sudhir sharma
Updated on 05-Aug-2020 07:59:26

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In this problem, we are given an array bin[] of size n of binary strings. Our task is to create a program to find the Bitwise OR (&) of n binary strings.Here, we will take all numbers and find the bitwise AND of them i.e. bin[0] | bin[1] |... bin[n-2] | bin[n]Let’s take an example to understand the problem, Input −bin[] = {“1001”, “11001”, “010101”}Output −011101Explanation − Bitwise OR of all binary string −(1001) | (11001) | (010101) = 011101To solve this problem, We will simply find the string with the largest number of bits (max length string). Then we ... Read More

Bitwise OR of a Range in C++

sudhir sharma
Updated on 05-Aug-2020 07:57:22

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In this problem, we are given two integer values a and b. And our task is to find the bitwise OR (|) of range from a to b. This means we will have to find the value of a | a+1 | a+2 | … b-1 | b.Let’s take an example to understand the problem, Input − a = 3 , b = 8Output − 15Explanation − 3 | 4 | 5 | 6 | 7 | 8 = 15To solve the problem, a simple solution is starting from a and find bit-wise OR of all numbers by increasing one ... Read More

Bitwise AND of Sub-array Closest to K in C++

sudhir sharma
Updated on 05-Aug-2020 07:55:34

1K+ Views

In this problem, we are given an array arr[] of size n and an integer k. Our task is to find the subarray within from index i to j and compute bitwise AND of all its elements. After this print minimum value of abs(K- (bitwise AND of subarray)).Let’s take an example to understand the problem, Input − arr[] = {5, 1}, k = 2Output −To solve the problem, there can be a few methods.One simple solution will be using the direct method. By finding bitwise AND for all sub-arrays then finding the |K-X|.Step 1 − Find the bitwise AND for ... Read More

Bitwise AND, OR and NOT Operations of a Range in C++

sudhir sharma
Updated on 05-Aug-2020 07:49:12

212 Views

In this problem, we are given two integer values a and b. And our task is to find the bitwise and (&) of range from a to b. This means we will have to find the value of a & a+1 & a+2 & … b-1 & b.Let’s take an example to understand the problem, Input − a = 3 , b = 8Output − 0Explanation − 3 & 4 & 5 & 6 & 7 & 8 = 0To solve the problem, a simple solution is starting from a and find bitwise and of all numbers by increasing one ... Read More

Important Tactics in C++ for Bit Manipulation

sudhir sharma
Updated on 05-Aug-2020 07:47:30

3K+ Views

Let’s first recall the about bits and the bitwise operator is short.Bit is a binary digit. It is the smallest unit of data that is understandable by the computer. In can have only one of the two values 0 (denotes OFF) and 1 (denotes ON).Bitwise operators are the operators that work a bit level in the program.These operators are used to manipulate bits in the program.In C, we have 6 bitwise operators −Bitwise AND (&)Bitwise OR (OR)Bitwise XOR (XOR)Bitwise left Shift (>)Bitwise not (~)https://www.tutorialspoint.com/cprogramming/c_bitwise_operators.htmNow, let’s learn some important tactics i.e. things that can be helpful if you work with bits.Swap ... Read More

Bitonic Sort in C++

sudhir sharma
Updated on 05-Aug-2020 07:44:00

1K+ Views

The bitonic sort is a parallel sorting algorithm that is created for best implementation and has optimum usage with hardware and parallel processor array.It is not the most effective one though as compared to the merge sort. But it is good for parallel implementation. This is due to the predefined comparison sequence which makes comparisons independent of data that are to be sorted.For bitonic sort to work effectively the number of elements should be in a specific type of quantity i.e. the order 2^n.One major part of the bitonic sort is the bitonic sequence which is a sequence whose elements ... Read More

Bitmasking and Dynamic Programming in C++

sudhir sharma
Updated on 05-Aug-2020 07:41:03

3K+ Views

First, we will learn about bitmasking and dynamic programming then we will solve a problem related to it that will solve your queries related to the implementation.Bitmask also known as mask is a sequence of N -bits that encode the subset of our collection. The element of the mask can be either set or not set (i.e. 0 or 1). This denotes the availability of the chosen element in the bitmask. For example, an element i is available in the subset if the ith bit of mask is set. For the N element set, there can be a 2N mask ... Read More

C Programming Language Standard

sudhir sharma
Updated on 05-Aug-2020 07:35:32

1K+ Views

In this problem, we will learn about the standards that are defined in the C programming language. These are those standard ways in which the program is to be ideally compiled by the compiler as defined by the development community.To understand what I am saying take an easy example of a common C program that you all must have encountered and have seen the issue coming but haven’t got deep into it.The main() function’s void return type −See the following program −void main() {    //program code }This program will run ok if we use the turbo c compiler but ... Read More

Store Student Records as Structures and Sort by Name in C

sudhir sharma
Updated on 05-Aug-2020 07:34:38

2K+ Views

In this problem, we are given a student’s record which contains student_id, student_name, student_percentage. Our task is to create a C program to store student records as structure and sort them by name.Let’s take an example to understand the problem, Input − student record ={{ student_id = 1, student_name = nupur, student_percentage = 98}, { student_id = 2, student_name = Akash, student_percentage = 75}, { student_id = 3, student_name = Yash, student_percentage = 62}, { student_id = 4, student_name = Jyoti, student_percentage = 87}, { student_id = 5, student_name = Ramlal, student_percentage = 80}}Output − student record ={{ student_id = ... Read More

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