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How to extract the names of vector values from a named vector in R?The names of vector values are created by using name function and the names can be extracted by using the same function. For example, if we have a vector called x that contains five values(1 to 5) and their names are defined as first, second, third, fourth and fifth then the names of values in x can be extracted by using names(x)[x==1].Example1Live Demo> x1 names(x1) x1Outputone two three four 1 2 3 4Example> names(x1)[x1==1]Output[1] "one"Example> names(x1)[x1==2]Output[1] "two" Example> names(x1)[x1==3]Output[1] "three"Example> names(x1)[x1==4]Output[1] "four" Example2Live Demo> x2 x2Output [1] ... Read More
Suppose we have a number n we have to generate nth term in “Look and Say” sequence. This is a sequence whose few terms are like below −111211211111221The string will be read like1 (One)11 (One 1) So read the previous 1, and say “One 1”21 (Two 1) So read the previous 11, and say “Two 1”1211 (One 2 one 1) So read the previous 21, and say “One 2 one 1”111221 (One 1 one 2 two 1) So read the previous 1211, and say “One 1 one 2 two 1”Suppose we have a number n, 1
The cartesian join is the joining of two objects that creates the combination of each value in object with all the values in the other object. For example, if we have a vector x that contains 1, 2, 3 and the other object y contains a, b, c then the cartesian join will be 1a, 2a, 3a, 1b, 2b, 3b, 1c, 2c, and 3c. Check out the below examples to understand how it can be done.Example> library(data.table) > DT1 DT1Output x 1: 1 2: 2 3: 3 4: 4Example> DT2 DT2Output y 1: 25 2: ... Read More
Suppose we have a string s where each characters are sorted and we also have a number k, we have to find the length of the longest substring such that every character occurs at least k times.So, if the input is like s = "aabccddeeffghij" k = 2, then the output will be 8, as the longest substring here is "ccddeeff" here every character occurs at least 2 times.To solve this, we will follow these steps −Define a function rc() . This will take lstc := a map with all characters and their occurrencesacc := a new listans := 0valid ... Read More
To find the column number of minimum values in each row for a data frame, we can use apply function but if we want to return the output in tabular form then matrix function should be used. For example, if we have a data frame df then our problem can be solved by using the code: as.matrix(apply(df, 1, which.min)).ExampleConsider the below data frame:Live Demo> set.seed(37) > x1 x2 x3 x4 x5 df1 df1Outputx1 x2 x3 x4 x5 1 1 2 4 9 3 2 0 5 8 10 4 3 1 3 8 6 1 4 1 5 5 8 ... Read More
Suppose we have a list of numbers called nums and another value k, we have to find the length of longest sublist where the absolute difference between the largest and smallest element is ≤ k.So, if the input is like nums = [2, 4, 6, 10] k = 4, then the output will be 3, as we can select pick [2, 4, 6] here the absolute difference is 4.To solve this, we will follow these steps −Create two double ended queue maxd, mindi := 0, res := 1for each index j and value a in A, dowhile maxd is not ... Read More
Suppose we have a binary list, so here only 1s and 0s are available and we also have another number k. We can set at most k 0s to 1s, we have to find the length of the longest sublist containing all 1s.So, if the input is like nums = [0, 1, 1, 0, 0, 1, 1] k = 2, then the output will be 6, as we can set the two middle 0s to 1s and then the list becomes [0, 1, 1, 1, 1, 1, 1].To solve this, we will follow these steps −zeros := 0, ans := ... Read More
The easiest way to replace numbers with ordinal strings is using ifelse function. The ifelse function in R works as ifelse(test_expression, x, y). Here, test_expression must be a logical vector or an object that can be coerced to logical). The return value is a vector with the same length as test_expression.Example1Live Demo> x1 x1Output[1] 1 1 1 0 1 0 0 1 1 1 0 0 1 0 1 0 0 1 1 0 0 1 1 1 1 0 0 0 0 1 1 1 0 1 1 0 1 [38] 0 1 1 0 0 1 0 1 ... Read More
Suppose we have a list of numbers called nums. We have to find the length of the longest sublist such that (minimum length 3) its values are strictly increasing and then decreasing.So, if the input is like nums = [7, 1, 3, 5, 2, 0], then the output will be 5, as the sublist is [2, 4, 6, 3, 1] is strictly increasing then decreasing.To solve this, we will follow these steps −i := 0, n := size of a, res := -infinitywhile i < n - 2, dost := ilinc := 0, ldec := 0while i < n - ... Read More
We can create a blank csv file using a single line code in R and the function that can do this is cat. If we want to have the file blank then NULL value will be passed inside the function and the file name must be used. For example, if we want to create a blank file named as BlankCSV then it can be created by using the below code:> cat(NULL, file="BlankCSV.csv")Output:This is the output from documents folder of the system where all the R files are stored by default(we can change that location if we want to):The output of ... Read More