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Input − Assume, you have a Series, a abc b 123 c xyz d ijkSolutionTo solve this, we will follow the steps given below −Define a SeriesGet the index from userSet the if condition to check the value is digit or not. It is defined below, if(data[x].isdigit()): print("digits present") else: print("not present")ExampleLet us see the following implementation to get a better understanding.import pandas as pd dic = {'a':'abc', 'b':'123', 'c':'xyz', 'd':'ijk'} data = pd.Series(dic) x = input("enter the index : ") if(data[x].isdigit()): print("digits present") else: print("not present")Outputenter the index : a not ... Read More
Input − Assume, you have a series,0 12 1 13 2 15 3 20 4 19 5 18 6 11Output − The result for the elements between 10 to 15 as,0 12 1 13 2 15 6 11Solution 1Define a SeriesCreate an empty list.Create for loop to access all the elements one by one and set if condition to compare the value from above or equal to 10 and below or equal to 15. Append matched values to an empty list as follows −for i in range(len(data)): if(data[i]>=10 and data[i]=10 and data[i]
Input − Assume, you have a series, 0 1 1 2 2 python 3 3 4 4 5 5 6 6.5Output −Total number of integer, float and string elements are, integer count: 5 float count: 1 string count: 1SolutionTo solve this, we will follow the steps given below −Define a Series.Create lambda filter method to extract the length of an integer value as follows, len(pd.Series(filter(lambda x:type(x)==int, data)Create lambda fliter method to extract length of float value as follows, len(pd.Series(filter(lambda x:type(x)==float, data)Create lambda fliter method to extract length of string value as follows, len(pd.Series(filter(lambda ... Read More
Solution 1Define lowercase alphabets in a list.Create for loop and find the even index elements and add it to another list. It is defined below ls = [] for i in l: if(l.index(i)%2==0): ls.append(i)Finally, apply random sample 5 values to the list and generate a series.Exampleimport pandas as pd import string import random as r chars = string.ascii_lowercase print("lowercase alphabets are:-", chars) chars_list = list(chars) data = r.sample(chars_list[::2], 5) print("random even index char's are:-", data) result = pd.Series(data) print("Series:", result)Outputlowercase alphabets are:- abcdefghijklmnopqrstuvwxyz random even index char's are:- ['w', 'k', 'i', 'u', ... Read More
Input − Assume, we have a Series, 0 2010-03-12 1 2011-3-1 2 2020-10-10 3 11-2-2Output − And, the result for valid dates in a series is, 0 2010-03-12 2 2020-10-10Solution 1Define a Series.Apply lambda filter method to validate a pattern in a series, data = pd.Series(l) result = pd.Series(filter(lambda x:re.match(r"\d{4}\W\d{2}\W\d{2}", x), data))Finally, check the result to the series using the isin() function.ExampleLet us see the following implementation to get a better understanding.import pandas as pd import re l = ['2010-03-12', '2011-3-1', '2020-10-10', '11-2-2'] data = pd.Series(l) for i, j in data.items(): if(re.match(r"\d{4}\W\d{2}\W\d{2}", j)): print(i, j)Output0 ... Read More
Input − Assume, you have a Series, 0 1 1 2 2 3 3 4 4 5Output −And, the result after replacing odd index with uppercase vowels as follows −0 1 1 A 2 3 3 U 4 5SolutionDefine a Series.Define uppercase alphabetsCreate lambda filter method and replace vowels in all index positions. It is defined belowvowels = re.findall(r'[AEIOU]', chars) result = pd.Series(filter(lambda x: r.choice(vowels) if(x%2!=0), l)data)Exampleimport pandas as pd import random as r l = [1, 2, 3, 4, 5] data = pd.Series(l) print(“Given series:”, data) vowels = list("AEIOU") ... Read More
Input − Assume you have the following series −0 1 1 2 2 python 3 pandas 4 3 5 4 6 5Output − The result for only integer elements are −0 1 1 2 4 3 5 4 6 5Solution 1Define a Series.Apply lambda filter method inside a regular expression to validate digits and expression accepts only strings so convert all the elements into strings. It is defined below, data = pd.Series(ls) result = pd.Series(filter(lambda x:re.match(r"\d+", str(x)), data))Finally, check the values using the isin() function.ExampleLet us ... Read More
Input − Assume, you have the following series, 0 1 1 2 2 3 3 4 4 5The above series contains no duplicate elements. Let’s verify using the following approaches.Solution 1Assume, you have a series with duplicate elements0 1 1 2 2 3 3 4 4 5 5 3Set if condition to check the length of the series is equal to the unique array series length or not. It is defined below, if(len(data)==len(np.unique(data))): print("no duplicates") else: print("duplicates found")Exampleimport pandas as pd import numpy as np data = ... Read More
We are required to write a JavaScript function that takes in an array of numbers as the first argument and a single number as the second argument. The function should then pick three such numbers from the array, (if they exist) whose sum is equal to the number specified by the second argument.The function should finally return an array of arrays of all such triplets if they exist, an empty array otherwise.For example −If the input array and the number is −const arr = [2, 5, 7, 8, 9, 11, 1, 6]; const sum = 22;Then the output should be ... Read More
Input −Assume you have a series, 0 14 1 16 2 30 3 49 4 80Output −The result for perfect square elements are, 0 4 1 16 3 49Solution 1We can use regular expression and lambda function filter method to find the perfect square values.Define a Series.Apply lambda filter method to check the value is a perfect square or not. It is defined below, l = [14, 16, 30, 49, 80] data=pd.Series([14, 16, 30, 49, 80]) result =pd.Series(filter(lambda x: x==int(m.sqrt(x)+0.5)**2, l))Finally, check the list of values to the series ... Read More