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Input − Assume, you have a series, 0 1 1 2 2 3 3 4Output − And, the result for the power of all elements in a series is, 0 1 1 4 2 27 3 256Solution 1Define a Series.Create transform method inside apply lambda power value. It is defined below, data.transform(lambda x:x**x)data.transform(lambda x:x**x)Solution 2Define a Series.Create an empty list. Create for loop, iter all the items. Append elements to the list. It is defined below, for i, j in data.items(): ls.append(m.pow(j, j))Finally, convert the list into Series.ExampleLet us see the ... Read More
Input −Assume, you have a series, 0 This is pandas 1 python script 2 pandas seriesOutput −And, the result after removing an element contains exactly two spaces, 1 python script 2 pandas seriesSolution 1Define a Series.Create lambda filter method to apply a regular expression to find the total number of spaces not equal to 2 as follows −pd.Series(filter(lambda x:len(re.findall(r" ", x))!=2, data))Finally, check the list of values to the series using isin().Solution 2Define a Series.Create for loop to iter the elements one by one and set if condition to count the spaces equal to 2. ... Read More
Input − Assume, you have a Series,0 abdef 1 ijkl 2 Abdef 3 oUijlOutput − And the result for all the elements in descending order,3 oUijl 1 ijkl 0 abdef 2 AbdefSolutionTo solve this, we will follow the steps given below −Define a SeriesApply sort_values method with the argument as ascending = False. It is defined below,data.sort_values(ascending=False)ExampleThe complete code listing is as follows,import pandas as pd l=["abdef","ijkl","Abdef","oUijl"] data=pd.Series(l) print("original series: ", data) print(data.sort_values(ascending=False))Output3 oUijl 1 ijkl 0 abdef 2 Abdef
Input − Assume, you have a Series, a abc b 123 c xyz d ijkSolutionTo solve this, we will follow the steps given below −Define a SeriesGet the index from userSet the if condition to check the value is digit or not. It is defined below, if(data[x].isdigit()): print("digits present") else: print("not present")ExampleLet us see the following implementation to get a better understanding.import pandas as pd dic = {'a':'abc', 'b':'123', 'c':'xyz', 'd':'ijk'} data = pd.Series(dic) x = input("enter the index : ") if(data[x].isdigit()): print("digits present") else: print("not present")Outputenter the index : a not ... Read More
Input − Assume, you have a series,0 12 1 13 2 15 3 20 4 19 5 18 6 11Output − The result for the elements between 10 to 15 as,0 12 1 13 2 15 6 11Solution 1Define a SeriesCreate an empty list.Create for loop to access all the elements one by one and set if condition to compare the value from above or equal to 10 and below or equal to 15. Append matched values to an empty list as follows −for i in range(len(data)): if(data[i]>=10 and data[i]=10 and data[i]
Input − Assume, you have a series, 0 1 1 2 2 python 3 3 4 4 5 5 6 6.5Output −Total number of integer, float and string elements are, integer count: 5 float count: 1 string count: 1SolutionTo solve this, we will follow the steps given below −Define a Series.Create lambda filter method to extract the length of an integer value as follows, len(pd.Series(filter(lambda x:type(x)==int, data)Create lambda fliter method to extract length of float value as follows, len(pd.Series(filter(lambda x:type(x)==float, data)Create lambda fliter method to extract length of string value as follows, len(pd.Series(filter(lambda ... Read More
Solution 1Define lowercase alphabets in a list.Create for loop and find the even index elements and add it to another list. It is defined below ls = [] for i in l: if(l.index(i)%2==0): ls.append(i)Finally, apply random sample 5 values to the list and generate a series.Exampleimport pandas as pd import string import random as r chars = string.ascii_lowercase print("lowercase alphabets are:-", chars) chars_list = list(chars) data = r.sample(chars_list[::2], 5) print("random even index char's are:-", data) result = pd.Series(data) print("Series:", result)Outputlowercase alphabets are:- abcdefghijklmnopqrstuvwxyz random even index char's are:- ['w', 'k', 'i', 'u', ... Read More
Input − Assume, we have a Series, 0 2010-03-12 1 2011-3-1 2 2020-10-10 3 11-2-2Output − And, the result for valid dates in a series is, 0 2010-03-12 2 2020-10-10Solution 1Define a Series.Apply lambda filter method to validate a pattern in a series, data = pd.Series(l) result = pd.Series(filter(lambda x:re.match(r"\d{4}\W\d{2}\W\d{2}", x), data))Finally, check the result to the series using the isin() function.ExampleLet us see the following implementation to get a better understanding.import pandas as pd import re l = ['2010-03-12', '2011-3-1', '2020-10-10', '11-2-2'] data = pd.Series(l) for i, j in data.items(): if(re.match(r"\d{4}\W\d{2}\W\d{2}", j)): print(i, j)Output0 ... Read More
Input − Assume, you have a Series, 0 1 1 2 2 3 3 4 4 5Output −And, the result after replacing odd index with uppercase vowels as follows −0 1 1 A 2 3 3 U 4 5SolutionDefine a Series.Define uppercase alphabetsCreate lambda filter method and replace vowels in all index positions. It is defined belowvowels = re.findall(r'[AEIOU]', chars) result = pd.Series(filter(lambda x: r.choice(vowels) if(x%2!=0), l)data)Exampleimport pandas as pd import random as r l = [1, 2, 3, 4, 5] data = pd.Series(l) print(“Given series:”, data) vowels = list("AEIOU") ... Read More
Input − Assume you have the following series −0 1 1 2 2 python 3 pandas 4 3 5 4 6 5Output − The result for only integer elements are −0 1 1 2 4 3 5 4 6 5Solution 1Define a Series.Apply lambda filter method inside a regular expression to validate digits and expression accepts only strings so convert all the elements into strings. It is defined below, data = pd.Series(ls) result = pd.Series(filter(lambda x:re.match(r"\d+", str(x)), data))Finally, check the values using the isin() function.ExampleLet us ... Read More