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To move a tick label without moving corresponding tick in Matplotlib, we can use axvline() method and can annotate it accordingly.StepsSet the figure size and adjust the padding between and around the subplots.Initialize a variable, delta.Create x and y data points using numpy.Plot delta using axvline() methodAnnotate that line using annotate() method.Plot x and y data points using plot() method.To display the figure, use show() method.Examplefrom matplotlib import pyplot as plt import numpy as np plt.rcParams["figure.figsize"] = [7.50, 3.50] plt.rcParams["figure.autolayout"] = True delta = 2.0 x = np.linspace(-10, 10, 100) y = np.sinc(x - delta) plt.axvline(delta, ls="--", ... Read More
To axes axis label object in Matplotlib, we can use ax.xaxis.get_label().get_text() method.StepsSet the figure size and adjust the padding between and around the subplots.Create a figure and a set of subplots.Initialize a variable, N, for number samples.Create random data points using numpy.Plot x data points using plot() method.Set X-axis label using set_xlabel() method.To get the xlabel, use get_label() method and get_text() method.To display the figure, use show() method.Exampleimport numpy as np import matplotlib.pyplot as plt plt.rcParams["figure.figsize"] = [7.50, 3.50] plt.rcParams["figure.autolayout"] = True fig, ax = plt.subplots() N = 100 x = np.random.rand(N) ax.plot(x) ax.set_xlabel("X-axis") x_lab = ax.xaxis.get_label() print("Label is: ... Read More
To adjust one subplot's height in absolute way in Matplotlib, we can take the following steps −Set the figure size and adjust the padding between and around the subplots.Create a new figure or activate an existing figure.For absolute height of subplot, use Axes() classAdd an axes to the figure.Plot the data points on the axes.To display the figure, use show() method.Examplefrom matplotlib import pyplot as pl pl.rcParams["figure.figsize"] = [7.50, 4.50] pl.rcParams["figure.autolayout"] = True figure = pl.figure() axes = pl.Axes(figure, [.4, .6, .25, .25]) figure.add_axes(axes) pl.plot([1, 2, 3, 4], [1, 2, 3, 4]) axes = pl.Axes(figure, [.4, ... Read More
Construct deterministic finite automata that accepts at most 3 a’s over an alphabet ∑={a,b}.At most 3 a’s means,The string contains 0 to max 3 a’s and any number of b’s.L= {Є,a,aa,aaa,ab,abb,bab,bbabaa, bbabaabbb,…..}Construct DFALet’s construct DFA step by step −Step 1Valid inputs − aaa, a, aa,ε .Step 2Valid inputs − b, ba, baa, baaa, bb, bba, bbba,…Step 3Valid input − bab, abba, abbbaa, babba,…Step 4Valid inputs − babab, aabb, aaba, bbbaaba, …Step 5Valid inputs − aaabbb, aaabab, baaaba, …Step 6InValid inputs − aaaa, aaabab, baaaba,
To calculate the curl of a vector field in Python and plot in with Matplotlib, we can use quiver() method and calculate the corresponding data.StepsSet the figure size and adjust the padding between and around the subplots.Create a new figure or activate an existing figure using figure() method.Add a 3D axes to the figure as part of a subplot arrangement.Create x, y and z data points using numpy meshgrid.Create u, v and w data curl vector positions.Use quiver() method to get vectors.Turn off the axes.To display the figure, use show() method.Exampleimport matplotlib.pyplot as plt import numpy as np plt.rcParams["figure.figsize"] ... Read More
CKY means Cocke-Kasami-Younger. It is one of the earliest recognition and parsing algorithms. The standard version of CKY can only recognize languages defined by context-free grammars in Chomsky Normal Form (CNF).It is also possible to extend the CKY algorithm to handle some grammars which are not in CNF (Hard to understand).Based on a “dynamic programming” approach −Build solutions compositionally from sub-solutionsIt uses the grammar directly.AlgorithmBegin for ( i = 1 to n do ) Vi1 { A | A → a is a production where i th symbol of x is a } for ( j = ... Read More
To clear a Matplotlib textbox that was previously drawn, we can take the following steps −Set the figure size and adjust the padding between and around the subplots.Create x and y data points using numpy.Plot x and y using plot() method.Place characters token on the plot.To clear the text, use text.remove(), where text is a returned artist.To display the figure, use show() method.Exampleimport numpy as np from matplotlib import pyplot as plt plt.rcParams["figure.figsize"] = [7.50, 3.50] plt.rcParams["figure.autolayout"] = True fig, ax = plt.subplots() x = np.linspace(-10, 10, 100) y = np.sin(x) ax.plot(x, y) text = fig.text(0.5, 0.96, ... Read More
ProblemConstruct DFA which accepts a string that contains second symbol is zero and fourth symbol is 1 over an alphabet ∑={0,1}.SolutionInput − 00110Output is accepted; because in the given string the second symbol is ‘0’ and the fourth symbol is ‘1’.Input − 11001Output − string is not accepted, because the second symbol is not ‘0’.Design DFA step by step as given below −Step 1 -Valid inputs − 0001Step 2 -Valid input − 1001Step 3 -Valid inputs − 0011, 1011Step 4 -Valid inputs − 00010, 10010, 00110, 00011, 10011, 00111, …Step 5 -Invalid inputs − 0101, 0100, 0010, 1100, 0000, 1000, …Step 6 -Valid inputs − 01010, 01000, 11111, 0100000, …
According to the theorem, If L and M are two regular languages, then L ∩ M is also regular language.ExampleConstruct A∩B where A and B is given as follows −The language A ={10, 100, 00, 001, 1010, …..}The language B ={01, 1010, 10, 101, …..}AA = (QA, Σ, δA, qa, FA) AB = (QB, Σ, δB, qB, FB) A∩B=(QA x QB ,Σ, δ(qA x qB ,FA x F B )Where, δ(( p, q), a) =δL (p, a), δM (q, a))Here, QA x QB = {p, q} x {r, s} ={(p, r), (p, s), (q, r), (q, s)} Z = ... Read More
ProblemConstruct a deterministic finite automata (DFA) that accepts a language L which has the number of zero’s is of multiple of 3 over an alphabet ∑=”{0,1}.SolutionIf input is: 000 Output is: string is acceptedBecause here the number of zero’s is multiple of 3.Designing DFAIn order to construct the DFA, follow the below mentioned steps −Step 1 -Valid inputs: 000, 000000, 09 , 012 , …Step 2 -Valid inputs: 1, 1000, 100000, …Step 3 -Valid inputs: 10100, 11000, 101100, …Step 4 -101010, 1101010, 1101110110, …Invalid inputs − 0,00,10000,01011, …