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Suppose we are given three integer numbers n, x, y, and z. We have to make a sequence from the given integers where the first item of the sequence is (x modulo 231). Other than the first element, other elements in the sequence ai = (a(i-1) * y + z) modulo 231 , where 1 ≤ i ≤ n - 1. We have to find out the number of distinct integers in the sequence we made.So, if the input is like n = 5, x = 1, y = 2, z = 1, then the output will be 5.The unique ... Read More
Suppose there is a film festival going on that showcase various movies from various countries. Now, an attendee wants to attend the maximum number of movies that do not overlap with each other and we have to help them to find out how many movies they can attend.There is a structure Movie that has the following members −The beginning time of the movie.The duration of the movie.The ending time of the movie.There is another structure Festival with the following members −The number of movies at the festival.An array of type Movie whose size is similar to the number of movies ... Read More
Suppose we are given a list that contains natural numbers. Now from that list, we remove all the numbers that contain two consecutive 1s in its binary representation and generate another list called Z. Now we are given another list 'input_list' that contains some integer values. We have to find out the XOR value of the specified elements from Z whose indexes are specified in input_list.So, if the input is like input_list = [3, 4, 5], then the output will be 9.In indexes 3, 4, and 5 of Z; the values are 4, 5, and 8. So, 4 XOR 5 ... Read More
Suppose we are given three integer numbers c, m, and n. We have to generate an infinite sequence, where the first value is 0, the second value is c, and from the third value onwards it is equal to ki = (ki-2 + ki-1) mod m. We have to generate all the values in the series up to item k2n+1. Now from the values of the series; we take two consecutive values in the sequence as the x and y coordinates of a two-dimensional vector and generate n number of vectors. Point to be noted, we use the values in ... Read More
To check if an Interval is closed on the left side, use the interval.closed_right property. At first, import the required libraries −import pandas as pdInterval set using the "closed" parameter with value "right" i.e. [0, 5) is described by 0 < x
Suppose we are given two integer numbers m and a. Now n = p1(a + 1) *p2(a + 2) *...*pm(a + m), where pi is the i-th prime number and i > 0. We have to find the value of k, where k = summation of f(x) values of n. Here f(x) values are the number of divisor values of each divisor of n.So, if the input is like m = 2, a = 1, then the output will be 60.So, n = 2^2 x 3^3n = 4 x 27n = 108The divisors of 108 are: 1, 2, 3, 4, ... Read More
Suppose we are given five integer numbers a, b, c, d, n. We have to find out ((ab)(cd)) mod n. The output value is an integer number.So, if the input is like a = 2, b = 3, c = 2, d = 4, n = 10, then the output will be 6.2^3 = 8 2^4 = 16 8^16 = 281474976710656 281474976710656 mod 10 = 6To solve this, we will follow these steps −Define a function helper() . This will take np := ni := 2while i * i 1, thenp := p - floor value of (p / ... Read More
To check whether the interval is closed on the left-side, right-side, both or neither, use the interval.closed property.At first, import the required libraries −import pandas as pdClosed interval set using the "closed" parameter with value "both". A closed interval (in mathematics denoted by square brackets) contains its endpoints, # i.e. the closed interval [0, 5] is characterized by the conditions 0
Suppose we are given a string and an integer k. The string is repeated k times and made to another string. Our task is to find the length of the substring in the new string where 2 * (number of zeroes in substring) 0: continue else: a = min(k - 1, -tmp // list_a[str_len]) v = a * list_a[str_len] - list_a[i] b = bisect_left(list_b, (-v + 1, 0)) - 1 res = max(res, temp_list[b] - i + a * str_len) return res print(solve(2, '0101011'))Input2, '0101011'Output14
To create a half-closed time interval, use the pandas.Interval() and set the closed parameter to right. To check for existence of endpoints, use the in property.At first, import the required libraries −import pandas as pdHalf-Closed interval set using the "closed" parameter with value "right". Half-Closed i.e. (0, 5] is described by 0 < x