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Articles on Trending Technologies
Technical articles with clear explanations and examples
Print the nodes at odd levels of a tree in C++ Programming.
Given the binary tree, the program must print the nodes at odd levels of a tree and the levels of a binary tree start from 1 to n.As nothing is mentioned one of the two approaches can be implemented i.e. recursion or iteration.Since we are using a recursive approach, the program will make a recursive call to a function that will be fetching the nodes at odd levels and returning them.In the above binary tree −Nodes at level 1: 10 Nodes at level 2: 3 and 211 Nodes at level 3: 140, 162, 100 and 146So, the nodes at level ...
Read MorePrint root to leaf paths without using recursion in C++ Programming.
Given the binary tree the program must find out the multiple paths from the root to a leaf which means all the paths should be printed but the challenge is to without using recursion.We will traverse the tree iteratively as the constraint is to do it without recursion. So to achieve this we can use an STL map that will store the root element and whenever the leaf node is identified through level order traversal it will print the path from root to leaf as there is a map pointer which is pointing to a root node.In the above tree, ...
Read MorePrint the first shortest root to leaf path in a Binary Tree in C++ Programming.
Given the binary tree the program must find out the shortest path from the root to leaf amongst many given paths.Since we traverse the tree from left to right, so if there are multiple shortest paths from the root to leaf than the program will print the first traversed the shortest path on the left side of a tree.We can use a queue that will traverse each level using Level order traversal and the path with the least number of levels will be printed as it will be the shortest path from the root to leafIn the above tree, multiple ...
Read MorePrint path between any two nodes in a Binary Tree in C++ Programming.
We are given with a binary tree of distinct nodes and two nodes of the binary tree whose path in the binary tree we want to print.For Example − We want to print the path between node 140 to 211 so its output should be like −Output: 140->3->10->211The idea is to find paths form root nodes to the two nodes and store them in two separate vectors or arrays say path1 and path2.Now, there arise two different cases −If the two nodes are in different subtrees of root nodes − When the two nodes are in different subtrees like one ...
Read MoreSplit the array into equal sum parts according to given conditions in C++
Here we will see one problem. Suppose one array arr is given. We have to check whether the array can be split into two parts, such that −Sub of both sub-arrays will be the sameAll elements, which are multiple of 5, will be in the same groupAll elements which are multiple of 3, but not multiple of 5, will be in the same groupAll other elements will be in other groups.Suppose the array elements are {1, 4, 3}, then this can be split, because the sum of {1, 3} is the same as the sum of {4}, and the groups ...
Read MoreMedian and Mode using Counting Sort in C++
Consider we have an array of size n, we have to find the Median and Mode using the counting sort technique. This technique is useful, when the array elements are in limited range. Suppose the elements are {1, 1, 1, 2, 7, 1}, then the Mode is 1, and Median is 1.5. Let us see what is Median and what is Mode −Median is the middle number in a sorted list of numbersMode is the element whose occurrences are maximum in the listTo get the Median and Mode, we have to follow these steps −Assume that the size of the ...
Read MoreMinimizing array sum by applying XOR operation on all elements of the array in C++
DescriptionGiven an array of size, N. Find an element X such that the sum of array elements should be minimum when XOR operation is performed with X and each element of an array.If input array is: arr [] = {8, 5, 7, 6, 9} then minimum sum will be 30 Binary representation of array elments are: 8 : 1000 5 : 0101 7 : 0111 6 : 0101 9 : 1001 If X = 5 then after performing XOR sum will be 30: 8 ^ 5 = 13 5 ^ 5 = 0 7 ^ 5 = 2 6 ^ ...
Read MorePrint the nodes of binary tree as they become the leaf node in C++ Programming.
Given a binary tree, we have to print its leaf nodes and then we have to remove those leaf nodes and then repeat till there are no nodes left in the tree.ExampleSo the output of the problem should be −6 7 9 13 14 3 4 2 1ApproachWe have adopted an approach where we are applying DFS.For applying a temporary value zero is assigned to every value and then assign all the nodes with the value maximum(value of both child)+1.AlgorithmSTART STEP 1-> DEFINE A struct Node WITH DATA MEMBERS data, order, *left, *right STEP 2-> DEFINE A struct Node* ...
Read MoreMinimum Cost To Make Two Strings Identical in C++
Suppose we have two strings A and B, and another two cost values like CostA, and CostB. We have to find the minimum cost to make A and B identical. We can delete characters from string, the cost for deleting from string A is CostA, and cost for deleting from string B is CostB. Cost of removing all characters from a string is same. Suppose the string A = “wxyz”, B = “wyzx”, CostA is 10 and CostB is 20. So the output will be 30. If we delete x from both the strings, then A and B will be ...
Read MoreMinimum Index Sum for Common Elements of Two Lists in C++
Suppose two person wants to choose different cities, they have listed out the cities in different list, we have to help the, to find common choices. So we need to find those cities, those are marked by both of them.This operation is very similar to the set intersection property, we will take two lists as set, then perform the set intersection to get the common elements.Example#include #include #include using namespace std; vector commonInterest(string set1[], int n1, string set2[], int n2) { vector v(min(n1, n2)); vector::iterator it; // Sorting both the list sort(set1, set1 ...
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