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Print path between any two nodes in a Binary Tree in C++ Programming.

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 555 Views

We are given with a binary tree of distinct nodes and two nodes of the binary tree whose path in the binary tree we want to print.For Example − We want to print the path between node 140 to 211 so its output should be like −Output: 140->3->10->211The idea is to find paths form root nodes to the two nodes and store them in two separate vectors or arrays say path1 and path2.Now, there arise two different cases −If the two nodes are in different subtrees of root nodes − When the two nodes are in different subtrees like one ...

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Split the array into equal sum parts according to given conditions in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 899 Views

Here we will see one problem. Suppose one array arr is given. We have to check whether the array can be split into two parts, such that −Sub of both sub-arrays will be the sameAll elements, which are multiple of 5, will be in the same groupAll elements which are multiple of 3, but not multiple of 5, will be in the same groupAll other elements will be in other groups.Suppose the array elements are {1, 4, 3}, then this can be split, because the sum of {1, 3} is the same as the sum of {4}, and the groups ...

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Median and Mode using Counting Sort in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 464 Views

Consider we have an array of size n, we have to find the Median and Mode using the counting sort technique. This technique is useful, when the array elements are in limited range. Suppose the elements are {1, 1, 1, 2, 7, 1}, then the Mode is 1, and Median is 1.5. Let us see what is Median and what is Mode −Median is the middle number in a sorted list of numbersMode is the element whose occurrences are maximum in the listTo get the Median and Mode, we have to follow these steps −Assume that the size of the ...

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Minimizing array sum by applying XOR operation on all elements of the array in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 316 Views

DescriptionGiven an array of size, N. Find an element X such that the sum of array elements should be minimum when XOR operation is performed with X and each element of an array.If input array is: arr [] = {8, 5, 7, 6, 9} then minimum sum will be 30 Binary representation of array elments are: 8 : 1000 5 : 0101 7 : 0111 6 : 0101 9 : 1001 If X = 5 then after performing XOR sum will be 30: 8 ^ 5 = 13 5 ^ 5 = 0 7 ^ 5 = 2 6 ^ ...

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Print the nodes of binary tree as they become the leaf node in C++ Programming.

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 231 Views

Given a binary tree, we have to print its leaf nodes and then we have to remove those leaf nodes and then repeat till there are no nodes left in the tree.ExampleSo the output of the problem should be −6 7 9 13 14 3 4 2 1ApproachWe have adopted an approach where we are applying DFS.For applying a temporary value zero is assigned to every value and then assign all the nodes with the value maximum(value of both child)+1.AlgorithmSTART STEP 1-> DEFINE A struct Node    WITH DATA MEMBERS data, order, *left, *right STEP 2-> DEFINE A struct Node* ...

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Minimum Cost To Make Two Strings Identical in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 277 Views

Suppose we have two strings A and B, and another two cost values like CostA, and CostB. We have to find the minimum cost to make A and B identical. We can delete characters from string, the cost for deleting from string A is CostA, and cost for deleting from string B is CostB. Cost of removing all characters from a string is same. Suppose the string A = “wxyz”, B = “wyzx”, CostA is 10 and CostB is 20. So the output will be 30. If we delete x from both the strings, then A and B will be ...

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Minimum Index Sum for Common Elements of Two Lists in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 252 Views

Suppose two person wants to choose different cities, they have listed out the cities in different list, we have to help the, to find common choices. So we need to find those cities, those are marked by both of them.This operation is very similar to the set intersection property, we will take two lists as set, then perform the set intersection to get the common elements.Example#include #include #include using namespace std; vector commonInterest(string set1[], int n1, string set2[], int n2) {    vector v(min(n1, n2));    vector::iterator it;    // Sorting both the list    sort(set1, set1 ...

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Find Corners of Rectangle using mid points in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 236 Views

Suppose we have a rectangle ABCD, but we have only the coordinates of the mid points P and Q, and the length of the rectangle L.Our task is to find the coordinates of A, B, C and D using the coordinates of P and Q, and the length of side L. For example, if P is (1, 0), and Q is (1, 2), and L is 2, then A, B, C, D will be respectively (0, 0), (0, 2), (2, 2). (2, 0).There can be three cases that can occur.The rectangle is horizontal, so AD and BC are parallel to ...

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Find the GCD of N Fibonacci Numbers with given Indices in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 274 Views

Here we have to find the GCD of n Fibonacci terms with the given indices. So at first we have to get the maximum index, and generate Fibonacci terms, some Fibonacci terms are like this: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ….. The index is starts from 0. So the element at 0th index is 0. If we have to find gcd of Fibonacci terms at indices {2, 3, 4, 5}, then the terms are {1, 2, 3, 4}, so GCD of these numbers are 1.We will use one interesting approach to do this task. To ...

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Find the Rotation Count in Rotated Sorted array in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 335 Views

Consider we have an array, which is rotated sorted array. We have to find number of rotations are required to sort the array. (We will consider rotation right to left.)Suppose the array is like: {15, 17, 1, 2, 6, 11}, then we have to rotate the array two times to sort. The final order will be {1, 2, 6, 11, 15, 17}. Here output is 2.The logic is simple. If we notice, we can see that the number of rotation is same as the value of index of minimum element. So if we get the minimum element, then its index ...

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