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# C++ program to find number of groups can be formed from set of programmers

Suppose we have an array A with n elements. The A[i] represents the programming skill of ith student. All elements in A are distinct. We want to split them into teams in such a way that −

No two students i and j, such that |A[i] - A[j]| = 1 belong to the same team

The number of teams is the minimum possible.

So, if the input is like A = [2, 3, 4, 99, 100], then the output will be 2, because the groups are [2, 3, 4] and [99, 100]

## Steps

To solve this, we will follow these steps −

dem := 1 sort the array A for initialize i := 1, when i < size of A, update (increase i by 1), do: if A[i] - A[i - 1] is same as 1, then: dem := 2 return dem

## Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h> using namespace std; int solve(vector<int> A) { int dem = 1; sort(A.begin(), A.end()); for (int i = 1; i < A.size(); i++) if (A[i] - A[i - 1] == 1) dem = 2; return dem; } int main() { vector<int> A = { 2, 3, 4, 99, 100 }; cout << solve(A) << endl; }

## Input

{ 2, 3, 4, 99, 100 }

## Output

2

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