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Technical articles with clear explanations and examples
Check if a large number can be divided into two or more segments of equal sum in C++
Here we will see a program, that can check whether a number can be divided into more than one segments with equal sum. Suppose a number is like 74325, then this can be segmented into three parts (7), (4, 3), (2, 5), all are of same um value.We have to follow these steps to solve this problem.Take the number as stringuse an array to hold prefix sum of the arrayNow traversing from second element to last element, and the first segment will be 0 to i-1, whose sum will be placed at prefix_sum[i - 1]Use another variable which traverses from ...
Read MoreProgram for octal to decimal conversion in C++
Given with an octal number as an input, the task is to convert the given octal number into a decimal number.Decimal numbers in computer is represented with base 10 and octal number is represented with base 8 starting from the digit 0 till 7 whereas decimal numbers can be any numeric digit starting from 0 – 9.To convert an octal number into a decimal number follow these steps −We will extract digits starting from right to left through a remainder and then multiply it with the power starting from 0 and will be increased by 1 till the (number of ...
Read MoreSort the numbers according to their sum of digits in C++
In this section we will see how to sort numbers according to their sum of digits. So if a number has lesser sum of digits, then that will be placed at first, then next number will be placed with larger sum of digits.data = {14, 129, 501, 23, 0, 145}after sorting, they will be −data = {0, 14, 23, 501, 145, 129}Here we will create our own comparison logic to sort them. That comparison logic will be used in the sort function in C++ STL.Algorithmcompare(num1, num2): Begin if sum of digits of num1 < sum of digits of num2, ...
Read MoreCheck if a number is Full Prime in C++
Here we will see, how to check, whether a number is full prime or not. A number is said to be a full prime, if it is prime, and all of its digits are also prime. Suppose a number is 37, this is full prime. But 97 is not full prime as 9 is not a prime number.One efficient approach is that; first we have to check whether any digit is present that is not prime. Digits must be in 0 to 9. In that range 2, 3, 5 and 7 are prime, others are not prime. If all are ...
Read MoreC++ Program to calculate Bitonicity of an Array
Given with an array of integers and the task is to calculate the bitonicity of a given array using a function.Bitonicity of an array is −Initialised to 0Incremented to 1 when the next element is greater than the previous valueDecremented to 1 when the next element is lesser than the previous valueExampleInput-: arr[] = { 1, 4, 3, 5, 2, 9, 10, 11} Output-: Bitonicity of an array is : 3Explanation −Initialize bitonicity calculating variable let’s say temp with 0.Start from the first element of an array which is 1. Now compare arr[i] and arr[i-1] i.e. compare 4 and 1 ...
Read MoreCheck if a large number is divisible by 13 or not in C++
Here we will see how to check a number is divisible by 13 or not. In this case the number is very large number. So we put the number as string.A number will be divisible by 13, if the number satisfies the following situations −A number is divisible by 13 if and only if we get the alternating sum i.e. alternatively adding and subtracting of blocks of three numbers from right to left is divisible by 13. For example, 2911285 is divisible by 13 because the alternating sum of blocks of size 3 is 2 – 911 + 285 = ...
Read MoreC++ program for hexadecimal to decimal
Given with a hexadecimal number as an input, the task is to convert the given hexadecimal number into a decimal number.Hexadecimal number in computers is represented with base 16 and decimal number is represented with base 10 and represented with values 0 - 9 whereas hexadecimal number have digits starting from 0 – 15 in which 10 is represented as A, 11 as B, 12 as C, 13 as D, 14 as E and 15 as F.To convert a hexadecimal number into a decimal number follow these steps −We will extract digits starting from right to left through a remainder ...
Read MoreHow many ways are there to initialize the instance variables of a class in java?
You can initialize the instance variables of a class using final methods, constructors or, Instance initialization blocks.Final methodsWhenever you make a method final, you cannot override it. i.e. you cannot provide implementation to the superclass’s final method from the subclass.i.e. The purpose of making a method final is to prevent modification of a method from outside (child class). You can also use these final methods to initialize the instance variables.Exampleimport java.util.Scanner; public class FinalMethods { int age = getAge(); String name = getName(); static Scanner sc = new Scanner(System.in); public static final int getAge() { ...
Read MoreTetranacci Numbers in C++
Here we will see how to generate the Tetranacci numbers using C++. The Tetranacci numbers are similar to the Fibonacci numbers, but here we are generating a term by adding four previous terms. Suppose we want to generate T(n), then the formula will be like below −T(n) = T(n - 1) + T(n - 2) + T(n - 3) + T(n - 4)The first few numbers to start, are {0, 1, 1, 2}Algorithmtetranacci(n): Begin first := 0, second := 1, third := 1, fourth := 2 print first, second, third, fourth for i in range n – ...
Read MoreC++ program for length of a string using recursion
Given with the string and the task is to calculate the length of the given string using a user defined function or in-built function.Length of a string can be calculated using two different ways −Using user defined function − In this, traverse the entire string until ‘\o’ is found and keep incrementing the value by 1 through recursive call to a function.Using user in-build function − There is an in-build function strlen() defined within “string.h” header file which is used for calculating the length of a string. This function takes single argument of type string and return integer value as ...
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