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# A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.

Given:

A ladder 10 m long reaches a window of a building 8 m above the ground.

To do:

We have to find the distance of the foot of the ladder from the building.

Solution:

Let $AB$ be the building and $AC$ be the ladder.

$BC$ is the length of the distance of the foot of the ladder from the building.

In right-angled $∆ABC$,

By Pythagoras theorem,

$AB^2 + BC^2 = AC^2$

$8^2 + BC^2 = 10^2$

$64 + BC^2 = 100$

$BC^2 = 100 - 64$

$BC^2 = 36$

$BC = \sqrt{36}\ m$

$BC = 6\ m$

Therefore, the distance of the foot of the ladder from the building is $6\ m$.

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