A ladder 17 m long reaches a window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.

Given:

A ladder 17 m long reaches a window of a building 15 m above the ground.

To do:

We have to find the distance of the foot of the ladder from the building.

Solution:

Let $AB$ be the building and $AC$ be the ladder.

$BC$ is the length of the distance of the foot of the ladder from the building.

In right-angled $∆ABC$,

By Pythagoras theorem,

$AB^2 + BC^2 = AC^2$

$15^2 + BC^2 = 17^2$

$225 + BC^2 = 289$

$BC^2 = 289 – 225$

$BC^2 = 64$

$BC = \sqrt{64}\ m$

$BC = 8\ m$

Therefore, the distance of the foot of the ladder from the building is $8\ m$.

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Updated on: 10-Oct-2022

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