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A $15\ m$ long ladder reached a window $12\ m$ high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.
Given: A $15\ m$ long ladder reached a window $12\ m$ high from the ground by placing it against a wall at a distance $a$.
To do: To find the distance of the foot of the ladder from the wall.
Solution:
Let $AC$ be the ladder, and $A$ be the window
$AC^2=AB^2+BC^2$
$\Rightarrow (15)^2=(a)^2+(12)^2$
$\Rightarrow 225-144=a^2$
$\Rightarrow 81=a^2$
$\Rightarrow \sqrt{81}=a$
$\Rightarrow a=9$
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