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What is the groups() method in regular expressions in Python?
The re.groups() method
This method returns a tuple containing all the subgroups of the match, from 1 up to however many groups are in the pattern. The default argument is used for groups that did not participate in the match; it defaults to None. In later versions (from 1.5.1 on), a singleton tuple is returned in such cases.
>>> m = re.match(r"(\d+)\.(\d+)", "27.1835") >>> m.groups() ('27', '1835')
If we make the decimal place and everything after it optional, not all groups might participate in the match. These groups will default to None unless the default argument is given −
>>> m = re.match(r"(\d+)\.?(\d+)?", "27") >>> m.groups() # Second group defaults to None. ('27', None) >>> m.groups('0') # Now, the second group defaults to '0'. ('27', '0')
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