Java program to find if the given number is a leap year?

Finding a year is a leap or not is a bit tricky. We generally assume that if a year number is evenly divisible by 4 is a leap year. But it is not the only case. A year is a leap year if −

  • 1. It is evenly divisible by 100
  • 2. If it is divisible by 100, then it should also be divisible by 400
  • 3. Except this, all other years evenly divisible by 4 are leap years.


  • 1. Take integer variable year
  • 2. Assign a value to the variable
  • 3. Check if the year is divisible by 4 but not 100, DISPLAY "leap year"
  • 4. Check if the year is divisible by 400, DISPLAY "leap year"
  • 5. Otherwise, DISPLAY "not leap year"


import java.util.Scanner;
public class LeapYear {
   public static void main(String[] args){
      int year;
      System.out.println("Enter an Year :: ");
      Scanner sc = new Scanner(;
      year = sc.nextInt();

      if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
         System.out.println("Specified year is a leap year");
         System.out.println("Specified year is not a leap year");

Output 1

Enter an Year ::
Specified year is a leap year

Output 2

Java Programming questions
Enter an Year ::
Specified year is not a leap year

Updated on: 07-Nov-2023

62K+ Views

Kickstart Your Career

Get certified by completing the course

Get Started