# Program to check if a given year is leap year in C

Leap year has 366 days whereas a normal year has 365 days and the task is to check through the program whether the given year is a leap year or not.

The logic for it can be through checking if year is divided by 400 or 4 but if the number is not divided by either of the number than it will be a normal year.

## Example

Input-: year=2000
Output-: 2000 is a Leap Year

Input-: year=101
Output-: 101 is not a Leap year

## Algorithm

Start
Step 1 -> declare function bool to check if year if a leap year or not
bool check(int year)
IF year % 400 = 0 || year%4 = 0
return true
End
Else
return false
End
Step 2 -> In main()
Declare variable as int year = 2000
Set check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year)
Set year = 10
Set check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year);
Stop

## Example

#include <stdio.h>
#include <stdbool.h>
//bool to check if year if a leap year or not
bool check(int year){
// If a year is multiple of 400 or multiple of 4 then it is a leap year
if (year % 400 == 0 || year%4 == 0)
return true;
else
return false;
}
int main(){
int year = 2000;
check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year);
year = 101;
check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year);
return 0;
}

## Output

2000 is a Leap Year
101 is not a Leap Year