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How to find a leap year using C language?
Leap year is a year that consists of 366 days. For every four years, we will experience a leap year.
The logic we will implement to find whether the given year by the user through the console is a leap or not −
if (( year%400 == 0)|| (( year%4 == 0 ) &&( year%100 != 0)))
If this condition is satisfied, then the given year is a leap year. Otherwise, it is not.
Example
Following is the C program to check leap year with the help of If condition −
#include <stdio.h>
int main(){
int year;
printf("Enter any year you wish
");
scanf(" %d ", &year);
if (( year%400 == 0)|| (( year%4 == 0 ) &&( year%100 != 0)))
printf("
%d is a Leap Year.
", year);
else
printf("
%d is not the Leap Year.
", year);
return 0;
}Output
When the above program is executed, it produces the following result −
Enter any year you wish 2045 2045 is not the Leap Year.
Updated on: 08-Mar-2021
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