How to handle a python exception within a loop?

PythonServer Side ProgrammingProgramming

We can the exception in the code by rewriting it as follows

a=[]
foo = 'redbullz'
try:
for i in foo:
a.append(i)
print a[8]
except Exception as e:
print e

We get following output

list index out of range
Process finished with exit code 0
raja
Updated on 27-Sep-2019 07:55:51

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