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How to handle an exception using lambda expression in Java?
A lambda expression body can't throw any exceptions that haven't specified in a functional interface. If the lambda expression can throw an exception then the "throws" clause of a functional interface must declare the same exception or one of its subtype.
Example
interface Student {
void studentData(String name) throws Exception;
}
public class LambdaExceptionTest {
public static void main(String[] args) {
// lamba expression
Student student = name -> {
System.out.println("The Student name is: " + name);
throw new Exception();
};
try {
student.studentData("Adithya");
} catch(Exception e) {
}
}
}Output
The Student name is: Adithya
Updated on: 10-Jul-2020
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