In this program we will see how to perform modulus of the first array corresponding to the next array.
Write 8086 Assembly language program perform modulus of the first array corresponding to the next array.
In this example there are two different arrays. The arrays are stored at location 501 onwards and 601 onwards. The size of these two arrays are stored at offset location 500. We are taking the array size to initialize the counter, then by using loops we are getting the modulus of the elements one by one
MOV SI, 500 ;Point Source index to 500 MOV CL, [SI] ;Load the array size into CL MOV CH, 00 ;Clear Upper half of CX INC SI ;Increase SI register to point next location MOV DI, 601 ;Destination register points to 601 L1: MOV AL, [SI] ;Load A with the data stored at SI MOV AH, 00 ;Clear upper half of AX DIV [DI] ;Subtract AX by DI MOV [SI], AH ;Store AH to SI address INC SI ;SI Point to next location INC DI ;DI Point to next location LOOP L1 ;Jump to L1 until the counter becomes 0 HLT ;Terminate the program