8085 program to take all numbers whose D7 and D1 are 0

Here we will see how we can take all numbers whose D7 and D1 bits are 0, using 8085.

Problem Statement

Write 8085 program to take all numbers from an array whose D7 and D1 bits are 0. Numbers are stored from 8001, and the array size is stored at 8000. Store the result from 9000 onwards.

Discussion

To solve this problem, we will AND the number by 82H (1000 0010). If the result is 0, then the number is acceptable. If the bit position D7 and D1 are 0, then only the result will be 0.

Input

Address	Data
…	…
8000	0A
8001	E9
8002	D3
8003	61
8004	AD
8005	2A
8006	1F
8007	5D
8008	A6
8009	A9
800A	35
…	…

Flow Diagram

Program

Address	HEX Codes	Labels	Mnemonics	Comments
F000	21, 00, 80		LXI H,8000	Load the size of array
F003	4E		MOV C,M	Store size into C
F004	11, 00, 90		LXI D,9000	Load the destination address
F007	23	LOOP	INX H	Point to next location
F008	7E		MOV A,M	Take number from memory to A
F009	E6, 82		ANI 82H	AND 82H with A
F00B	C2, 10, F0		JNZ SKIP	if A is not 0, then skip it
F00E	12		STAX D	Else store A into memory pointed by DE
F00F	13		INX D	point to next location
F010	0D	SKIP	DCR C	decrease counter by 1
F011	C2, 07, F0		JNZ LOOP	if c is not 0, jump to LOOP
F014	76		HLT	Terminate the program

Output

Address	Data
…	…
9000	61
9001	54
9002	35
…	…

Ankith Reddy

Updated on: 30-Jul-2019

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