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# 8085 program to find the factorial of a number

In this program we will see how to find the factorial of a number.

## Problem Statement

Write 8085 Assembly language program to find the factorial of an 8-bit number.

## Discussion

In 8085, there is no direct instruction to perform multiplication. We need to perform repetitive addition to get the result of the multiplication. In each step we are decreasing the value of B and multiply with the previous value of B. We are repeating these steps until B reaches 1. and B – 1 to 0. Thus the factorial is generated.

## Input

Address | Data |
---|---|

8000 | 05 |

## Flow Diagram

## Program

Address | HEX Codes | Labels | Mnemonics | Comments |
---|---|---|---|---|

F000 | 21, 00, 80 | | LXI H, 8000H | Load the number |

F003 | 46 | | MOV B,M | Take number from memory to B |

F004 | 16, 01 | | MVI D, 01H | Set D to 01H |

F006 | CD, 10, F0 | FACT | CALL MUL | Call multiplication |

F009 | 05 | | DCR B | Decrease B by 1 |

F00A | C2, 06, F0 | | JNZ FACT | If Z = 0, jump to Fact |

F00D | 23 | | INX H | Point to next location |

F00E | 72 | | MOV M,D | Store result in memory |

F00F | 76 | | HLT | Terminate the program |

F010 | 58 | MUL | MOV E,B | Load B to E |

F011 | AF | | XRA A | Clear accumulator to store result |

F012 | 82 | ML | ADD D | Add D to A |

F013 | 1D | | DCR E | Decrement E |

F014 | C2, 12, F0 | | JNZ ML | If Z = 0, jump to ML |

F017 | 57 | | MOV D,A | Transfer contents of A to D |

F018 | C9 | | RET | Return result |

## Output

Address | Data |
---|---|

8001 | 78 |

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