Java.math.BigDecimal.compareTo() Method



The java.math.BigDecimal.compareTo(BigDecimal val) compares the BigDecimal Object with the specified BigDecimal value.

Two BigDecimal objects that are equal in value but have a different scale (like 2.0 and 2.00) are considered equal by this method.

This method is provided in preference to individual methods for each of the six boolean comparison operators (<, ==, >, >=, !=, <=).

The suggested idiom for performing these comparisons is: (x.compareTo(y) <op> 0), where <op> is one of the six comparison operators.

Specified by

compareTo in interface Comparable<BigDecimal>


Following is the declaration for java.math.BigDecimal.compareTo() method

public int compareTo(BigDecimal val)


  • val - value to which this BigDecimal is to be compared

Return Value

This method returns -1 if the BigDecimal is less than val, 1 if the BigDecimal is greater than val and 0 if the BigDecimal is equal to val


  • NA


The following example shows the usage of math.BigDecimal.compareTo() method.

package com.tutorialspoint;

import java.math.*;

public class BigDecimalDemo {

public static void main(String[] args) {

        // create 2 BigDecimal objects
        BigDecimal bg1, bg2;

        bg1 = new BigDecimal("10");
        bg2 = new BigDecimal("20");

        //create int object
        int res;

        res = bg1.compareTo(bg2); // compare bg1 with bg2

        String str1 = "Both values are equal ";
	String str2 = "First Value is greater ";
	String str3 = "Second value is greater";

	if( res == 0 )
	System.out.println( str1 );
	else if( res == 1 )
	System.out.println( str2 );
	else if( res == -1 )
	System.out.println( str3 );

Let us compile and run the above program, this will produce the following result:

Second value is greater