What does fluent wait perform?

JavascriptDOM

Fluent wait is a dynamic wait which makes the driver pause for a condition which is checked at a frequency before throwing an exception. The element is searched in DOM not constantly but at a regular interval of time.

For example, if the wait is for 5 seconds, FluentWait monitors the DOM at regular intervals (defined by polling during time). In FluentWait, customized wait methods based on conditions need to be built.

Syntax

Wait<WebDriver> w = new FluentWait< WebDriver >(driver)
.withTimeout (10, SECONDS)
.pollingEvery (2, SECONDS)
.ignoring (NoSuchElementException.class)

Example

import org.openqa.selenium.By;
import org.openqa.selenium.Keys;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import java.util.concurrent.TimeUnit;
import org.openqa.selenium.support.ui.Wait;
import org.openqa.selenium.support.ui.FluentWait;
public class Fluentwt {
   public static void main(String[] args) {
      System.setProperty("webdriver.chrome.driver", "C:\\Users\\ghs6kor\\Desktop\\Java\\chromedriver.exe");
      WebDriver driver = new ChromeDriver();
      String url = "https://www.tutorialspoint.com/index.htm";
      driver.get(url);
      //implicit wait with time in seconds applied to each elements
      driver.manage().timeouts().implicitlyWait(12, TimeUnit.SECONDS);
      //Clicking on Coding Ground link
      driver.findElement(By.xpath("//span[text()=’Coding Ground’]")).click();
      // fluent wait declaration
      Wait<WebDriver> w = new FluentWait<WebDriver>(driver).withTimeout
      (Duration.ofSeconds(30))
      .pollingEvery(Duration.ofSeconds(3)).ignoring(
      NoSuchElementException.class);
      WebElement fl = w.until(new Function<WebDriver, WebElement>() {
         // customized condition for fluent wait
         public WebElement apply(WebDriver driver) {
            if (driver.findElement(By.xpath("[//img[@title=’Whiteboard’"))
            .isDisplayed()) {
               return true;
            }else {
               return null;
            }
         }
      });
      driver.quit();
   }
}
raja
Published on 10-Jun-2020 18:08:47
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