There are 6 marbles in a box with numbers from 1 to 6 marked on each of them.
$(i)$. What is the probability of drawing a marble with the number 2?
$(ii)$. What is the probability of drawing a marble with the number 5?

Given:

Total number of marbles from 1 to 6 marked in a box $=6$.

To do:

We have to find:

(i) The probability of drawing a marble with the number 2.

(ii) The probability of drawing a marble with the number 5.

Solution:

Here,

The total number of possible outcomes: $n(S)=6$

As known,

Probability $=\frac{ \text { Number of favorable outcomes }}{ \text { Total number of possible outcomes }}$

(i) Number of marbles marked with $2=1$

Thus, number of favorable outcome : $n(E)=1$

Therefore, P(probability of drawing a marble with number 2) $=\frac{n(E)}{n(S)}$ 

$=\frac{1}{6}$

(ii) Number of marbles marked with 5 $=1$

Thus, number of favourable outcome: $n(E)=1$

Therefore, P(probability of drawing a marble with number 5) $=\frac{n(E)}{n(S)}$

$=\frac{1}{6}$