There are 6 marbles in a box with numbers from 1 to 6 marked on each of them.
$(i)$. What is the probability of drawing a marble with the number 2?
$(ii)$. What is the probability of drawing a marble with the number 5?
Given:
Total number of marbles from 1 to 6 marked in a box $=6$.
To do:
We have to find:
(i) The probability of drawing a marble with the number 2.
(ii) The probability of drawing a marble with the number 5.
Solution:
Here,
The total number of possible outcomes: $n(S)=6$
As known,
Probability $=\frac{ \text { Number of favorable outcomes }}{ \text { Total number of possible outcomes }}$
(i) Number of marbles marked with $2=1$
Thus, number of favorable outcome : $n(E)=1$
Therefore, P(probability of drawing a marble with number 2) $=\frac{n(E)}{n(S)}$
$=\frac{1}{6}$
(ii) Number of marbles marked with 5 $=1$
Thus, number of favourable outcome: $n(E)=1$
Therefore, P(probability of drawing a marble with number 5) $=\frac{n(E)}{n(S)}$
$=\frac{1}{6}$
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