The probability of getting an even number, when a dice is thrown once, is:

$( A)\frac{1}{2}$
$( B)\frac{1}{3}$
$( C)\frac{1}{6}$
$( D)\frac{5}{6}$

Given: A dice is thrown once.

To do: To find the probability of getting an even number when the dice is thrown. 

Solution: When a dice is thrown,

There are total possible outcomes$( 1,2,3,4,5,6) =6$

Number of favourable outcomes $( 2,\ 4,\ 6) =3$

Probability of favourable outcomes$=\frac{no.\ of\ favourble\ outcomes}{no.\ of\ total\ outcomes} =\frac{3}{6} =\frac{1}{2}$ 

Therefore the probability of getting an even number, when a dice is thrown is $\frac{1}{2}$.

$\therefore$ Option $( A)$  is correct.

 

Updated on: 10-Oct-2022

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