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# The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

**Given:**The far point of a myopic person is 80 cm in front of the eye.

**To:**To find the nature and power of the lens required to correct the problem.

**Solution:**

The person is suffering from myopia. And this person needs a concave lens to correct the defect. The lens should be such that an object at infinity must form its image at the far point of $80\ cm$ to make it visible to the myopic person.

The power of the lens can be obtained as:

**The formula for the power of the lens$\rightarrow$**

$\boxed{P=\frac{1}{f}}$

$P\rightarrow$ Power of the lens

$f\rightarrow$ focal length of the lens

It is given, $f=-80\ cm=-0.8\ m$

$P=\frac{1}{-0.8\ m}$

$=-1.25\ D$

Therefore,

**Power of the lens:**

The power of the lens is $-1.25\ D$.

**Nature of the lens:**

$(-ve)$ sign implies that it is a concave lens. It is diverging in nature.

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