Swift Double - squareRoot() Function

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The squareRoot() method of the Double structure is used to calculate the square root of the given value.

For example, suppose we have number = 8.0. Using the squareRoot() method, we find its square root, which is 2.8284271247461903.

Syntax

Following is the syntax of the squareRoot() function −

func squareRoot()

Parameter

This method does not take any parameters.

Return Value

This method returns the square root of the given value.

Example 1

Swift program to demonstrate how to use the squareRoot() method:

import Foundation

// Input numbers
var number1 : Double = 8.0
var number2 : Double = 4.0
var number3 : Double = 17.0

// Finding square root using squareRoot() method
var result1 = number1.squareRoot()
var result2 = number2.squareRoot()
var result3 = number3.squareRoot()

// Display result
print("Square root of \(number1):", result1)
print("Square root of \(number2):", result2)
print("Square root of \(number3):", result3)

Output

Square root of 8.0: 2.8284271247461903
Square root of 4.0: 2.0
Square root of 17.0: 4.123105625617661

Example 2

Swift program to calculate the square root of given numbers:

import Foundation

// Finding square root using squareRoot() method
var result1 = 14.squareRoot()
var result2 = 12.2.squareRoot()
var result3 = 56.8.squareRoot()

// Display result
print("Square root of 14:", result1)
print("Square root of 12.2:", result2)
print("Square root of 56.8:", result3)

Output

Square root of 14: 3.7416573867739413
Square root of 12.2: 3.492849839314596
Square root of 56.8: 7.536577472566709

Example 3

Swift program to calculate the hypotenuse of a triangle using the squareRoot() method:

import Foundation

// Function to calculate the hypotenuse of a triangle
func triHypotenuse(x: Double, y: Double) -> Double {
   return (x * x + y * y).squareRoot()
}

let result = triHypotenuse(x: 5, y: 7)

print("Hypotenuse of the triangle is", result)

Output

   Hypotenuse of the triangle is 8.602325267042627