State whether the following statements are true or false. Justify your answer.
(i) $sin\ (A + B) = sin\ A + sin\ B$.
(ii) The value of $sin\ θ$ increases as $θ$ increases.
(iii) The value of $cos\ θ$ increases as $θ$ increases.
(iv) $sin\ θ = cos\ θ$ for all values of $θ$.
(v) $cot\ A$ is not defined for $A = 0^o$.
To find:
We have to state whether the given statements are true or false.
Solution:
(i) Let $\mathrm{A}=30^{\circ}$ and $\mathrm{B}=60^{\circ}$
This implies,
LHS $=\sin (30^{\circ}+60^{\circ})=\sin 90^{\circ}$
$=1$
RHS $=\sin 30^{\circ}+\sin 60^{\circ}$
$=\frac{1}{2}+\frac{\sqrt3}{2}$
$=\frac{1+\sqrt3}{2}$
LHS $≠$ RHS
Hence, the given statement is false.
(ii) We know that,
$\sin 0^{\circ}=0$
$\sin 30^{\circ}=\frac{1}{2}$
$\sin 45^{\circ}=\frac{1}{\sqrt{2}}$
$\sin 60^{\circ}=\frac{\sqrt{3}}{2}$
$\sin 90^{\circ}=1$
Therefore, the value of $\sin\ \theta$ increases as $\theta$ increases.
Hence, the given statement is true.
(iii) We know that,
$\cos 0^{\circ}=1$
$\cos 30^{\circ}=\frac{\sqrt3}{2}$
$\cos 45^{\circ}=\frac{1}{\sqrt{2}}$
$\cos 60^{\circ}=\frac{1}{2}$
$\cos 90^{\circ}=0$
Therefore, the value of $\cos\ \theta$ decreases as $\theta$ increases.
Hence, the given statement is false.
(iv) We know that,
$\sin 0^{\circ}=0$
$\cos 0^{\circ}=1$
$\sin 0^{\circ}≠\cos 0^{\circ}$
Therefore, $\sin \theta$ is not always equal to $\cos \theta$
Hence, the given statement is false.
(v) We know that,
$\cot 0^{\circ}=\frac{\cos 0^{\circ}}{\sin 0^{\circ}}$
$=\frac{1}{0}$
$\frac{1}{0}$ is not defined.
Hence, the given statement is true.
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