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Sorting contents of a string that holds integer values in Java
To sort the string that contains numbers in java −
Get the String.
Create an empty integer array.
The split() method of the string class accepts a string representing a delimiter, splits the current string into an array of tokens. Using this method split the given string into an array of tokens.
The parseInt() method of the Integer class accepts a String value and converts it into an integer. Convert each element in the String array obtained in the previous step into an integer and store in into the integer array.
The sort() method of the Arrays class accepts an array, sorts the contents of it in ascending order. Sort the integer array using this method.
Example
public class SortingStrings {
public static void main(String args[]) {
String str = "22 58 69 63 69 55 669 24 4285 654 1 296 564 2 582 255 562";
System.out.println("Contents of the string: "+ str);
//Splitting the String array
String[] stringArray = str.split(" ");
//Converting each element into an integer
int [] intArray = new int[stringArray.length];
for(int i = 0; i < stringArray.length; i++) {
intArray[i] = Integer.parseInt(stringArray[i]);
}
Arrays.sort(intArray);
System.out.println("Sorted integer values: "+Arrays.toString(intArray));
}
}Output
Contents of the string: 22 58 69 63 69 55 669 24 4285 654 1 296 564 2 582 255 562 Sorted integer values: [1, 2, 22, 24, 55, 58, 63, 69, 69, 255, 296, 562, 564, 582, 654, 669, 4285]
Updated on: 11-Oct-2019
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