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# Smallest Integer Divisible by K in Python

Suppose we have a positive integer K, we need find the smallest positive integer N such that N is divisible by K, and N only contains the digit 1. We have to find the length of N. If there is no such N, return -1. So if the input is like 3, then the output will be 3. The smallest answer will be N = 111.

To solve this, we will follow these steps −

- if k is even, or k is divisible by 5, then return -1
- set r := 0 and N = 1
- for i in range 1 to K + 1
- r := (r * 10 + 1) mod k
- if r = 0, then return i

Let us see the following implementation to get better understanding −

## Example

class Solution(object): def smallestRepunitDivByK(self, K): if K%2==0 or K%5 ==0: return -1 r = 0 N=1 for i in range(1,K+1): r = (r*10 + 1)%K if r == 0: return i ob = Solution() print(ob.smallestRepunitDivByK(11))

## Input

11

## Output

2

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