Smallest Integer Divisible by K in Python

Suppose we have a positive integer K, we need find the smallest positive integer N such that N is divisible by K, and N only contains the digit 1. We have to find the length of N. If there is no such N, return -1. So if the input is like 3, then the output will be 3. The smallest answer will be N = 111.

To solve this, we will follow these steps −

• if k is even, or k is divisible by 5, then return -1
• set r := 0 and N = 1
• for i in range 1 to K + 1
  • r := (r * 10 + 1) mod k
  • if r = 0, then return i

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution(object):
   def smallestRepunitDivByK(self, K):
      if K%2==0 or K%5 ==0:
         return -1
      r = 0
      N=1
      for i in range(1,K+1):
         r = (r*10 + 1)%K
         if r == 0:
            return i
ob = Solution()
print(ob.smallestRepunitDivByK(11))

Input

11

Output

2

Arnab Chakraborty

Updated on: 30-Apr-2020

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