# C++ Program for Smallest K digit number divisible by X?

C++Server Side ProgrammingProgramming

In this problem we will try to find smallest K-digit number, that will be divisible by X. To do this task we will take the smallest K digit number by this formula (10^(k-1)). Then check whether the number is divisible by X or not, if not, we will get the exact number by using this formula.

(min+ 𝑋)−((min+ 𝑋) 𝑚𝑜𝑑 𝑋)

One example is like a 5-digit number, that is divisible by 29. So the smallest 5-digit number is 10000. This is not divisible by 29. Now by applying the formula we will get −

(10000+ 29)−((10000+29) 𝑚𝑜𝑑 29)=10029−24=10005

The number 10005 is divisible by 29.

## Algorithm

### minKDigit(k, x)

begin
min = 10 ^ (k-1)
if min is divisible by x, return min
otherwise return (min + x) – ((min + x) mod x)
end

## Example

Live Demo

#include<iostream>
#include<cmath>
using namespace std;
long min_k_digit(int k, int x) {
//get the minimum number of k digits
int min = pow(10, k-1);
if(min % x == 0) {
return min;
}
return (min + x) - ((min + x) % x);
}
main() {
int k, x;
cout << "Enter Digit Count(K) and Divisor(N): ";
cin >> k >> x;
cout << "Result is: " << min_k_digit(k, x);
}

## Output

Enter Digit Count(K) and Divisor(N): 5 29
Result is: 10005

## Output

Enter Digit Count(K) and Divisor(N): 6 87
Result is: 100050
Published on 24-Jul-2019 13:00:48