- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Single Number in Python
Suppose we have an array A. In this array there are many numbers that occur twice. Only one element can be found a single time. We have to find that element from that array. Suppose A = [1, 1, 5, 3, 2, 5, 2], then the output will be 3. As there is each number twice, we can perform XOR to cancel out that element. because we know y XOR y = 0
To solve this, we will follow these steps.
- Take one variable res = 0
- for each element e in array A, preform res = res XOR e
- return res
Example
Let us see the following implementation to get a better understanding −
class Solution(object): def singleNumber(self, nums): """ :type nums: List[int] :rtype: int """ ans = nums[0] for i in range(1,len(nums)): ans ^=nums[i] return ans ob1 = Solution() print(ob1.singleNumber([1,1,5,3,2,5,2]))
Input
nums = [1,1,5,3,2,5,2]
Output
3
Advertisements