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Returning only odd number from array in JavaScript
Problem
We are required to write a JavaScript function that takes in an array of integers, arr, as the first and the only argument.
The array either consists of all even numbers and just one odd number or consists of all odd numbers and just one even number. Our function should return this one different element from the array.
For example, if the input to the function is −
Input
const arr = [5, 9, 7, 11, 34, 23, 77];
Output
const output = 34;
Output Explanation
Because the array consists of all odd numbers but 34 which is even.
Example
Following is the code −
const arr = [5, 9, 7, 11, 34, 23, 77];
const findDifferent = (arr = []) => {
let { length: len } = arr, i;
const evens = [];
const odds = [];
let k;
for (i=0; i<len; i++) {
if (arr[i] % 2 == 0) {
evens.push(arr[i]);
};
if (Math.abs(arr[i] % 2) == 1) {
odds.push(arr[i]);
};
};
if (evens.len > odds.len)
return odds[0];
else
return evens[0];
};
console.log(findDifferent(arr));Output
34
Updated on: 22-Apr-2021
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