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Finding the only out of sequence number from an array using JavaScript
Problem
We are required to write a JavaScript function that takes in an array of numbers. The array is sorted in ascending / increasing order and only one element in the array is out of order.
Our function should find and return that element.
Example
Following is the code −
const arr = [1, 2, 3, 4, 17, 5, 6, 7, 8];
const findWrongNumber = (arr = []) > {
for(let i = 0; i < arr.length - 1; i++){
const el = arr[i];
if(el - arr[i + 1] < 0 && arr[i + 1] - arr[i + 2] > 0){
return arr[i + 1];
}
};
};
console.log(findWrongNumber(arr));Output
17
Updated on: 20-Apr-2021
370 Views
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