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Python program to print the elements of an array present on odd position
When it is required to print the elements of a list that is present in odd index/position, a loop can be used to iterate over the elements, and only check the odd positions in the list by specifying the step size as 2 in the range function.
Below is a demonstration of the same −
Example
my_list = [31, 42, 13, 34, 85, 0, 99, 1, 3]
print("The list is :")
print(my_list)
print("The elements in odd positions are : ")
for i in range(1, len(my_list), 2):
print(my_list[i])Output
The list is : [31, 42, 13, 34, 85, 0, 99, 1, 3] The elements in odd positions are : 42 34 0 1
Explanation
A list is defined, and is displayed on the console.
The list is iterated over beginning from the second index element, and the step size is mentioned as 2 in the range method.
Those elements that are in odd positions are displayed on the console.
Updated on: 16-Apr-2021
2K+ Views
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