# Python program to print odd numbers in a list

In this article, we will learn about the solution and approach to solve the given problem statement.

## Problem statement

Given a list iterable as input, we need to display odd numbers in the given iterable.

Here we will be discussing three different approaches to solve this problem.

## Approach 1 − Using enhanced for loop

### Example

list1 = [11,23,45,23,64,22,11,24]
# iteration
for num in list1:
# check
if num % 2 != 0:
print(num, end = " ")

### Output

11, 23, 45, 23, 11

## Approach 2 − Using lambda & filter functions

### Example

Live Demo

list1 = [11,23,45,23,64,22,11,24]
# lambda exp.
odd_no = list(filter(lambda x: (x % 2 != 0), list1))
print("Odd numbers in the list: ", odd_no)

### Output

Odd numbers in the list: [11, 23, 45, 23, 11]

## Approach 3 − Using the list comprehension

### Example

Live Demo

list1 = [11,23,45,23,64,22,11,24]
#list comprehension
odd_nos = [num for num in list1 if num % 2 != 0]
print("Odd numbers : ", odd_nos)

### Output

Odd numbers in the list: [11, 23, 45, 23, 11]

## Conclusion

In this article, we learned about the approach to find all odd numbers in the list given as input.