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In this article, we will learn about the solution to the problem statement given below.

**Problem statement **− We are given a list, we need to count even and odd numbers in a list.

There are three methods as discussed below−

list1 = [21,3,4,6,33,2,3,1,3,76] even_count, odd_count = 0, 0 # enhanced for loop for num in list1: #even numbers if num % 2 == 0: even_count += 1 #odd numbers else: odd_count += 1 print("Even numbers available in the list: ", even_count) print("Odd numbers available in the list: ", odd_count)

Even numbers available in the list: 4 Odd numbers available in the list: 6

list1 = [21,3,4,6,33,2,3,1,3,76] #odd numbers odd_count = len(list(filter(lambda x: (x%2 != 0) , list1))) #even numbers even_count = len(list(filter(lambda x: (x%2 == 0) , list1))) print("Even numbers available in the list: ", even_count) print("Odd numbers available in the list: ", odd_count)

Even numbers available in the list: 4 Odd numbers available in the list: 6

list1 = [21,3,4,6,33,2,3,1,3,76] #copy of list elements which are odd in a new list and calculating the length on new list only_odd = [num for num in list1 if num % 2 == 1] odd_count = len(only_odd) print("Even numbers available in the list: ", len(list1) - odd_count) print("Odd numbers available in the list: ", odd_count)

Even numbers available in the list: 4 Odd numbers available in the list: 6

In this article, we have learned how to count even and odd numbers in a list.

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