Python program to check if binary representation is palindrome?

Here we use different python inbuilt function. First we use bin() for converting number into it’s binary for, then reverse the binary form of string and compare with originals, if match then palindrome otherwise not.

Example

Input: 5
Output: palindrome

Explanation

Binary representation of 5 is 101

Reverse it and result is 101, then compare and its match with originals.

So its palindrome

Algorithm

Palindromenumber(n)
/* n is the number */
Step 1: input n
Step 2: convert n into binary form.
Step 3: skip the first two characters of a string.
Step 4: them reverse the binary string and compare with originals.
Step 5: if its match with originals then print Palindrome, otherwise not a palindrome.

Example code

# To check if binary representation of a number is pallindrome or not
defpalindromenumber(n): 
   # convert number into binary bn_number = bin(n)      
   # skip first two characters of string
   # Because bin function appends '0b' as 
   # prefix in binary 
   #representation of a number bn_number = bn_number[2:]
   # now reverse binary string and compare it with original
   if(bn_number == bn_number[-1::-1]):
      print(n," IS A PALINDROME NUMBER")
   else:
      print(n, "IS NOT A PALINDROME NUMBER")
# Driver program
if __name__ == "__main__":
   n=int(input("Enter Number ::>"))
   palindromenumber(n)

Output

Enter Number ::>10
10 IS NOT A PALINDROME NUMBER
Enter Number ::>9
9 IS A PALINDROME NUMBER

Samual Sam

Learning faster. Every day.

Updated on: 30-Jul-2019

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