Python program to check if binary representation of two numbers are anagram.

Given two numbers. Our task is to check whether they are anagrams of each other or not in binary representation. We can solve this problem quickly in python using Counter (iterable) method and Dictionary Comparison.

Examples

Input: a = 8, b = 16
Output : Yes
Binary representations of both numbers have same 0s and 1s.


Algorithm

Step 1 : Given two numbers.
Step 2 : Convert both number into its binary using bin() function and remove first two characters because of bin().
Step 3 : Since binary representation of both numbers could differ in length so we will append zeroes in start of   shorter string to make both string of equal length.
Step 4 : Compare both dictionaries, if value of 0’s and 1’s in both dictionaries are equal then binary representations of two numbers are anagram otherwise not. Binary representations into dictionary.


Example Code

# function to Check if binary representations
# of two numbers are anagram
from collections import Counter

def anagramoftwonumber(p1,p2):
# convert numbers into in binary
# and remove first two characters of
# output string because bin function
#'0b' as prefix in output string
bno1 = bin(p1)[2:]
bno2 = bin(p2)[2:]

# append zeros in shorter string
zeros = abs(len(bno1)-len(bno2))
if (len(bno1)>len(bno2)):
bno2 = zeros * '0' + bno2
else:
bno1 = zeros * '0' + bno1

# convert binary representations
# into dictionary
dict1 = Counter(bno1)
dict2 = Counter(bno2)

# compare both dictionaries
if dict1 == dict2:
print(p1, p2 ,"are two anagram number")
else:
print(p1 , p2 ,"are not anagram number")

# Driver program
if __name__ == "__main__":
n1 = int(input("Enter First number ::>"))
n2 = int(input("Enter Second number ::>"))
anagramoftwonumber(n1,n2)


Output

Enter First number ::>8
Enter Second number ::>16
8 16 are two anagram number

Enter First number ::>3
Enter Second number ::>2
3 2 are not anagram number