# Python Program to Check Armstrong Number

In this article, we will learn about the solution and approach to solve the given problem statement.

## Problem statement

Given an integer n , we need to check that the given integer is an armstrong number.

A positive integer is called an Armstrong number of order n if

abcd... = a^n + b^n + c^n + d^n + …

Here we will be discussing the brute-force approach for an armstrong number of 3 digits and hence of order three.

To check the armstrong number of order n we need to replace 3 by the corresponding order value in line number 7.

Now let’s see the implementation −

## Example

Live Demo

num = 221
sum_ = 0
#
temp = num
while temp > 0:
digit = temp % 10
sum_ += digit ** 3
temp //= 10
#
if num == sum_:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")

## Output

221 is not an Armstrong number

All variables and functions are declared in the global scope as shown in the figure below.

## Conclusion

In this article, we learned about the approach to check whether a given number is an armstrong number or not.