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Check the number is Armstrong or not using C
Problem
How to check whether the given number is an Armstrong number or not using C Programming language?
Solution
Armstrong number is the number that is equal to the sum of cubes of its digits.
Syntax
pqrs………=pow(p,n)+pow(q,n)+pow(r,n)+……….
For example, 153,371,1634, etc., are Armstrong numbers.
153=1*1*1 + 5*5*5 + 3*3*3 =1+125+27 =153 (Armstrong number)
Program
#include<stdio.h>
int main(){
int number,remainder,total=0,temp;
printf("enter the number=");
scanf("%d",&number);
temp=number;
while(number>0){
remainder=number%10;
total=total+(remainder*remainder*remainder);
number=number/10;
}
if(temp==total)
printf("This number is Armstrong number");
else
printf("This number is not Armstrong number");
return 0;
}Output
enter the number=371 This number is Armstrong number Check: 371=3*3*3 +7*7*7 + 1*1*1 =27 + 343 +1 =371 enter the number=53 This number is not Armstrong number
Explanation
53 = 5*5*5 + 3*3*3 =125 +27 = 152 != 53
Updated on: 05-Mar-2021
8K+ Views
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