# Check the number is Armstrong or not using C

CServer Side ProgrammingProgramming

## Problem

How to check whether the given number is an Armstrong number or not using C Programming language?

## Solution

Armstrong number is the number that is equal to the sum of cubes of its digits.

## Syntax

pqrs………=pow(p,n)+pow(q,n)+pow(r,n)+……….

For example, 153,371,1634, etc., are Armstrong numbers.

153=1*1*1 + 5*5*5 + 3*3*3
=1+125+27
=153 (Armstrong number)

## Program

Live Demo

#include<stdio.h>
int main(){
int number,remainder,total=0,temp;
printf("enter the number=");
scanf("%d",&number);
temp=number;
while(number>0){
remainder=number%10;
total=total+(remainder*remainder*remainder);
number=number/10;
}
if(temp==total)
printf("This number is Armstrong number");
else
printf("This number is not Armstrong number");
return 0;
}

## Output

enter the number=371
This number is Armstrong number
Check: 371=3*3*3 +7*7*7 + 1*1*1
=27 + 343 +1
=371
enter the number=53
This number is not Armstrong number

## Explanation

53 = 5*5*5 + 3*3*3
=125 +27
= 152 != 53