Python program to accept the strings which contains all vowels

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Sometimes you want to accept input based on certain conditions. Here, we are going to see the same type of program. We will write a program that allows only words with vowels. We will show them whether the input is valid or not.

Let's see the approach step by step.

  • Define a list of vowels [A, E, I, O, U, a, e, i, o, u]

  • Initialize a word or sentence.

  • Iterate over the word or sentence.

    • Check if it is present in the list or not.      

3.1.1. If not, break the loop and print Not accepted.
  • Else print accepted


Let's convert the text into Python code.

def check_vowels(string):
   # vowels
   vowels = ['A', 'E', 'I', 'O', 'U', 'a', 'e', 'i', 'o', 'u']
   # iterating over the string
   for char in string:
      if char not in vowels:
      print(f"{string}: Not accepted")
      print(f"{string}: Accepted")
if __name__ == '__main__':
   # initializing strings
   string_1 = "tutorialspoint"
   string_2 = "AEiouaieeu"
   # checking the strings


If you run the above code, you will get the following results.

tutorialspoint: Not accepted
AEiouaieeu: Accepted


You check different properties based on your requirements. If you have any doubts in the tutorial, mention them in the comment section.

Updated on 12-Feb-2020 12:28:45