Python Program for Stooge Sort

In this article, we will learn about the solution to the problem statement given below.

Problem statement − We are given an array, we need to sort it using stooge sort.


1. Check if value at index 0 is greater than value at last index,then swap them.
2. sort the initial 2/3rd of the array.
3. sort the last 2/3rd of the array.
4. sort the initial 2/3rd again to confirm.

Now let’s observe the solution in the implementation below −


 Live Demo

def stoogesort(arr, l, h):
   if l >= h:
   # swap
   if arr[l]>arr[h]:
      t = arr[l]
      arr[l] = arr[h]
      arr[h] = t
   # more than 2 elements
   if h-l+1 > 2:
      t = (int)((h-l+1)/3)
      # sort first 2/3 elements
      stoogesort(arr, l, (h-t))
      # sort last 2/3 elements
      stoogesort(arr, l+t, (h))
      # sort first 2/3 elements again
      stoogesort(arr, l, (h-t))
# main
arr = [1,4,2,3,6,5,8,7]
n = len(arr)
stoogesort(arr, 0, n-1)
print ("Sorted sequence is:")
for i in range(0, n):
   print(arr[i], end = " ")


Sorted sequence is:
1 2 3 4 5 6 7 8

All the variables are declared in the local scope and their references are seen in the figure above.

Conclusion −

In this article, we have learned about how we can make a Python Program for Stooge Sort

Updated on: 20-Dec-2019


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