Program to find number of steps required to change one word to another in Python

PythonServer Side ProgrammingProgramming

Suppose we have a list of words called dictionary and we have another two strings start and end. We want to reach from start to end by changing one character at a time and each resulting word should also be in the dictionary. Words are case-sensitive. So we have to find the minimum number of steps it would take to reach at the end. If it is not possible then return -1.

So, if the input is like dictionary = ["may", "ray", "rat"] start = "rat" end = "may", then the output will be 3, as we can select this path: ["rat", "ray", "may"].

To solve this, we will follow these steps −

dictionary := a new set with all unique elements present in
q = a double ended queue with a pair (start, 1)
while q is not empty, do
   (word, distance) := left element of q, and delete the left element
   if word is same as end, then
      return distance
      for i in range 0 to size of word - 1, do
         for each character c in "abcdefghijklmnopqrstuvwxyz", do
            next_word := word[from index 0 to i - 1] concatenate c concatenate word[from index (i + 1) to end]
            if next_word is in dictionary, then
               delete next_word from dictionary
               insert (next_word, distance + 1) at the end of q
return -1

Example (Python)

Let us see the following implementation to get better understanding −

 Live Demo

from collections import deque
class Solution:
   def solve(self, dictionary, start, end):
      dictionary = set(dictionary)
      q = deque([(start, 1)])
      while q:
         word, distance = q.popleft()
         if word == end:
            return distance
         for i in range(len(word)):
            for c in "abcdefghijklmnopqrstuvwxyz":
               next_word = word[:i] + c + word[i + 1 :]
               if next_word in dictionary:
                  dictionary.remove(next_word)
                  q.append((next_word, distance + 1))
      return -1
ob = Solution()
dictionary = ["may", "ray", "rat"]
start = "rat"
end = "may"
print(ob.solve(dictionary, start, end))

Input

["may", "ray", "rat"], "rat", "may"

Output

3
raja
Published on 12-Dec-2020 09:04:55
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